Rectangle ABCD is shown to the right. Point E is located

Mathematics

1 answer:

mafiozo [28]3 years ago

4 0

A) The area of the rectangle ABCD is base times height. 20in x 12in = 240 in sq.
B) The area of the triangle AED is base times height divided by two. (14in x 12in)/2 = 84in sq.
C) Figure EBCD is a right trapezoid (having one pair of parallel sides, while the others are slanted and forming a right angle).
D) Area of EBCD is the area of the rectangle minus the area of the triangle. 240in sq - 84in sq = 156in sq.

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If a boy 5 feet tall casts a shadow 14 feet long, what will be the length of the shadow of a tree that is 25 feet high?

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Step-by-step explanation:

This problem can be answered by using proportions based on similar triangles.

Notice that a person and its shadow on the ground form a right angle (therefore they can be considered the two "legs" of a right angle triangle)

The same runs for the tree and its shadow.

Since the inclination of the rays of the sun are the same at the same time for both objects (the boy and the tree), their hypothenuses form the same angles with the ground and therefore belong to similar triangles.

We can create the following proportion to solve for the shadow of the tree (ST) using the information provided: the height of the boy (HB), the shadow of the boy (SB), and the height of the tree (HT)

$\frac{SB}{HB} =\frac{ST}{HT}\\\frac{14}{5} =\frac{ST}{25}\\\frac{ST}{25}=\frac{14}{5} \\ST=\frac{14*25}{5}\\ST=70\,\,ft$