The answer is No solution
Answer:
Exercise 1:
base [b]=8cm
perpendicular [p]=6cm
hypotenuse [h]=?
<u>By</u><u> </u><u>using</u><u> </u><u>Pythagoras</u><u> </u><u>law</u>
h²=p²+b²
h²=6²+8²
h=√100
h=10cm
<u>So</u><u> </u><u>another</u><u> </u><u>side's</u><u> </u><u>length</u><u> </u><u>is</u><u> </u><u>1</u><u>0</u><u>c</u><u>m</u>
<u>Exercise</u><u> </u><u>2</u><u>:</u>
base [b]=6m
perpendicular [p]=bm
hypotenuse [h]=8m
By using Pythagoras law
h²=p²+b²
8²=b²+6²
b²=8²-6²
b=√28=2√7 0r 5.29 or 5.3
So height of kite is√<u>28</u><u>o</u><u>r</u><u> </u><u>2√7 0r 5.29 or 5.3 m</u>
Step-by-step explanation:
[Note: thanks for translating]
The answer is <span>0.118 seconds</span>.
The velocity (v) is the distance (d) divided by time (t):
v = d ÷ t
It is given:
v = 3.00 × 10⁸ meters per second
d = 3.54 × 10⁷ meters
It is unknown:
t = ?
If:
<span>v = d ÷ t
</span>Then:
<span>t = d ÷ v
</span>t = 3.54 × 10⁷ meters ÷ <span>3.00 × 10⁸ meters/second
t = 1.18 </span>× 10⁻¹ seconds
t = 0.118 seconds
Therefore, radio signal will travel from a satellite to the surface ofEarth 0.118 seconds.
5÷3=1.7
Donna used about 1.7 tubes of glitter for each poster.
I'm pretty sure this is it because when you divide this you get 1.6 repeating and you get 1.7 when you round it.