Answer:
y>3x -1 is the right answer
Answer:
b+6
Problem:
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Step-by-step explanation:
We are given (b+c)/2=8 and d=3b-4.
We are asked to find (c+d)/2 in terms of variable, b.
We need to first solve (b+c)/2=8 for c.
Multiply both sides by 2: b+c=16.
Subtract b on both sides: c=16-b
Now let's plug in c=16-b and d=3b-4 into (c+d)/2:
([16-b]+[3b-4])/2
Combine like terms:
(12+2b)/2
Divide top and bottom by 2:
(6+1b)/1
Multiplicative identity property applied:
(6+b)/1
Anything divided by 1 is that anything:
(6+b)
6+b
b+6
Answer:
<h2>621.207km</h2>
Step-by-step explanation:
We are expected to convert from miles to kilometer
first day 85 miles =136.794km
Second day 125 mile=201.168km
third day 176 miles =283.245km
Total distance covered is
136.794km+201.168km+283.245km=621.207km
Therefore the total distance in kilometer is 621.207km
Answer
The answer is 567
Step-by-step explanation:
189*3=567
