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3 years ago

A plant grew 3 1/4 inches over a 6 1/2 month period.what was the average monthly growth rate for the plant

Mathematics

1 answer:

Solnce55 [7]3 years ago

5 0

Answer:

0.5 inches per a month

Step-by-step explanation:

you turn them to a decimal to make them easier and then divide them to get the answer.

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The table shows the estimated number of bees, y, in a hive x days after a pesticide is released near the hive.

Oksana_A [137]

Answer:

Step-by-step explanation:

The given table is

Days Bees

0 10,000

10 7,500

20 5,600

30 4,200

40 3,200

50 2,400

Where $x$ represents days and $y$ represents bees.

The exponential function that models this problem must be like

$y=a(1-r)^{x}$ , which represenst an exponential decary, because in this case, the number of bees decays.

We nned to use one points, to find the rate of decay. We know that $a=10,000$ , because it starts with 10,000 bees.

Let's use the points (10, 7500)

$y=a(1-r)^{x}\\7500=10000(1-r)^{10}$

Solving for $r$ , we have

$\frac{7500}{10000}=(1-r)^{10} \\(1-r)^{10} =0.75$

Using logarithms, we have

$ln((1-r)^{10}) =ln(0.75)\\10 \times ln(1-r)=ln(0.75)\\ln(1-r)=\frac{ln(0.75)}{10} \approx -0.03\\e^{ln(1-r)}=e^{-0.03}\\1-r =e^{-0.03}\\r=-e^{-0.03}+1 \approx 1.97$

Replacing all values in the model, we have

$y=10000(1-1.97)^{x}\\y=10000(0.97)^{x}$

Therefore, the right answer is the first choice, that's the best approximation to this situation.

6 0

2 years ago

Read 2 more answers

Consider a normal distribution with mean 23 and standard deviation 7. What is the probability a value selected at random from th

Trava [24]

Answer:

0.5 = 50% probability a value selected at random from this distribution is greater than 23

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 23, \sigma = 7$