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Ymorist [56]
3 years ago
9

BRAINLIEST for the right answer!!!

Mathematics
1 answer:
nikitadnepr [17]3 years ago
6 0
The answer is D, $23,500
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The specification for the pull strength of a wire that connects an integrated circuit to its frame is 10 g or more. In a sample
Wittaler [7]

Answer:

The 95% confidence interval for the difference is (-0.1888, 0.0202).

Step-by-step explanation:

Difference between proportions:

The distribution of the difference between two proportions has mean of the difference between these proportions and standard deviation is the square root of the sum of the variances. So

In a sample of 86 units made with gold wire, 68 met the specification

This means that:

pX = \frac{68}{86} = 0.7907

sX = \sqrt{\frac{0.7907*0.2093}{86}} = 0.0439

In a sample of 120 units made with aluminum wire, 105 met the specification.

This means that:

pY = \frac{105}{120} = 0.875

sY = \sqrt{\frac{0.875*0.125}{120}} = 0.0302

Difference:

p = pX - pY = 0.7907 - 0.875 = -0.0843

s = \sqrt{sX^2 + sY^2} = \sqrt{0.0439^2+0.0302^2} = 0.0533

Confidence interval:

p \pm zs

In which z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}, with \alpha being 1 subtracted by the confidence level.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Lower bound of the interval:

p - zs = -0.0843 - 1.96*0.0533 = -0.1888

Upper bound of the interval:

p + zs = -0.0843 + 1.96*0.0533 = 0.0202

The 95% confidence interval for the difference is (-0.1888, 0.0202).

6 0
3 years ago
What’s bigger 1.30 or 1.3
Firdavs [7]

they are both the same

7 0
3 years ago
For what natural values of n is the difference (2−2n)−(5n−27) positive?
pashok25 [27]

(2−2n)−(5n−27) >0

distribute

2-2n -5n +27 >0

combine like terms

-7n +29 >0

subtract 29 from each side

-7n> -29

divide by -7  (flips the inequality)

n < -29/-7

n <4.14

natural numbers are 1,2,3,4......

n must be 1,2,3,4

Answer: 1,2,3,4

4 0
3 years ago
Read 2 more answers
A population of 50 timber wolves was introduced into a forest in 2009. The population is expected to grow by the function p(t)=5
Viktor [21]

Answer:

the population in 2015 is 8201.0695

Step-by-step explanation:

Given that

There is a population of the 50 timber wolves

And, the exponential function given is

p(t) = 50 × e^(0.85 × t)

Here t denotes the time period i.e.

= 2015 - 2009

= 6

So,

= 50 × e^(0.85 × 6)

= 8201.095

Hence, the population in 2015 is 8201.0695

8 0
3 years ago
What is the approximate solution to the equation 3^t=29 ? a) 0.3263 b)3.0650 c) 3.3672 d) 9.6667
Vinvika [58]

Answer:

b

Step-by-step explanation:

using the law of logarithms

• log x^{n} = nlogx

given 3^{t} = 29 ( take log of both sides, that is base 10 )

log 3^{t} = log 29, hence

tlog 3 = log29 (divide both sides by log 3 )

t = \frac{log29}{log3} ≈ 3.0650 → b



7 0
3 years ago
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