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maria [59]
3 years ago
5

Sarah saw a hammer that was $3.50 more than twice the cost of a screwdriver. The hammer was $15.50. What was the cost of the scr

ewdriver?
Mathematics
1 answer:
joja [24]3 years ago
7 0

Answer:

$6

Step-by-step explanation:

$15.50 is $3.50 more than $12. And $12 is twice $6. The cost of the screwdriver is $6.

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Multiply. Write in simplest form 3/10 x 8
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Answer:

2.4

Step-by-step explanation:

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If you're room is 86 inches and you're bed is 60 inches can you put a 80 centimeters chest fit next to the bed
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yes i think so

Step-by-step explanation:

Queen 60" X 80" 152 X 203.5cm

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If ON= 5x - 7, LM = 4x+ 4, NM = x -7, and OL =3y-4, find the values of c and y for which LMNO MUST BE a parallelogram.
Sholpan [36]

Answer:

x=11, y=8/3

Step-by-step explanation:

Consider quadrilateral LMNO. If this quadrilateral MUST BE a parallelogram, then

LM=NO

and

LO=MN

Thus,

\left\{\begin{array}{l}4x+4=5x-7\\ \\x-7=3y-4\end{array}\right.

Solve this system of two equations. From the first equation:

4x-5x=-7-4\\ \\-x=-11\\ \\x=11

Substitute it into the second equation:

11-7=3y-4\\ \\3y-4=4\\ \\3y=4+4\\ \\3y=8\\ \\y=\dfrac{8}{3}

4 0
3 years ago
Algebra 2 (picture shown)
TEA [102]

Answer:

<em>M(13)=14.3 gram</em>

Step-by-step explanation:

<u>Exponential Decay Function</u>

The exponential function is used to model natural decaying processes, where the change is proportional to the actual quantity.

An exponential decaying function is expressed as:

C(t)=C_o\cdot(1-r)^t

Where:

C(t) is the actual value of the function at time t

Co is the initial value of C at t=0

r is the decaying rate, expressed in decimal

The element has an initial mass of Mo=970 grams, the decaying rate is r=27.7% = 0.277 per minute.

The equation of the model is:

M(t)=M_o\cdot(1-r)^t

M(t)=970\cdot(1-0.277)^t

Operating:

M(t)=970\cdot 0.723^t

After t=13 minutes the remaining mass is:

M(13)=970\cdot 0.723^{13}

Calculating:

M(13)=14.3 gram

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A researcher randomly surveyed two separate age groups to determine the number of hours teens spend on the Internet each week. T
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The answer to this is A.
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