Answer:
Hope this helps you
Step-by-step explanation:
43. A "Square" cornfield, which means all 4 sides has the same lenght BxH
164.000 ft^2=404.96 NO
156.816 ft^2=396 Yes
174724 ft^2=418 Yes
215908 ft^2=464.66 NO
44. it's the same here, if the area is 81. then each side of the square is 9
1st figure: it has 12 sides x9 =108
2nd figure: it has 10 sides x9=90
3rd figure: has also 12 sides x9=108
45. 13^3= 13x13x13 = 2197
46. 25^2= 25x25 = 625
47. 15^3= 15x15x15 = 3375
48. 34^2= 34x34 = 1156
49. 5 root121= 5 (11)=55
50. -6.root36= - 6 (6)= -36
51. 10 root3 (8) = 10(2) = 20
52. -4. root 144= -4(12) = -48
• Given the table of values, you can identify these points:
If you plot them on a Coordinate Plane, you get:
As you can observe, it is a Linear Function.
• The equation of a line in Slope-Intercept Form is:
Where "m" is the slope of the line and "b" is the y-intercept.
In this case, you can identify in the graph that:
Therefore, you can substitute that value and the coordinates of one of the points on the line, into this equation:
And then solve for "m", in order to find the slope of the line.
Using this point:
You get:
Therefore, the equation for the data in Slope-Intercept Form is:
Hence, the answer is:
• It represents a Linear Function.
,
• Equation:
Answer:
37. {-1, -1}.
Step-by-step explanation:
I'll solve the first one . The other can be solved in a similar way. We can use the method of elimination.
x1 - x2 = 0
3x1 - 2x2 = -1
We can multiply the first equation by -2. We then have an equation containing + 2x2 so when we add this to the second equation the 2x2 will be eliminated
So the first equation becomes:
-2x1 + 2x2 = 0 Bring down the second equation:
3x1 - 2x2 = -1 Now adding, we get:
x1 + 0 = -1
so x1 = -1.
Now we substitute this value of x1 in the original first equation:
-1 - x2 = 0
-1 = x2
x2 = -1.
So the solution set is {-1, -1}.
If there are more than 2 equations you can use a combination of substitutions and eliminations.
A and C are similar but not congruent
I believe the GCF for the park 4 and 49 is 1.
