PLEASEEEEE HELPPPP ASAPPPPPP FIND THE SLOPE
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Answer:
The coordinates of the vertex are (4 , 16)
Step-by-step explanation:
The coordinates of the vertex of a parabola which represents a quadratic equation y = ax² + bx + c are (h , k), where
- h =
- k is the value of y at x = h
∵ The equation of the parabola is y = - x² + 8x
- Compare it by the form of the equation above to find a, b and c
∵ a is the coefficient of x²
∴ a = -1
∵ b is the coefficient of x
∴ b = 8
∵ c is the numerical term
∴ c = 0
The vertex of the parabola is (h , k)
∵ h =
- Substitute the values of a and b
∴ h =
∴ h = 4
∵ k = y at x = h
- Substitute x by 4 and y by k in the equation
∵ k = - (4)² + 8(4)
∴ k = -16 + 32
∴ k = 16
∴ The coordinates of the vertex are (4 , 16)
The true statement is (a) segment BC is located at B (1, 0) and C (1, 3) and is one-half the size of segment B'C'
The coordinates are given as:
The scale factor from BC is given as:
So, the coordinates of segment BC are calculated using:
This gives
Divide both sides by 2
Also, we have:
Divide both sides by 2
Hence, the true statement is (a)
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