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IRINA_888 [86]
3 years ago
13

Calculate the velocity of a moving train with a mass 10,000kg and 150,000J of energy.

Mathematics
1 answer:
Viefleur [7K]3 years ago
5 0
Kinetic energy possessed by moving train is E_k = 150000J.

And mass m = 10000kg.

The formula for kinetic energy is E_k = \frac{m\times v^2}{2}.

Solve for velocity:

E_k = \frac{m\times v^2}{2}\implies 2E_k = m\times v^2

v^2=\frac{2E_k}{m}\implies \underline{v = \sqrt{\frac{2E_k}{m}}}

Now put in the data:

v = \sqrt{\frac{2\times150000J}{10000kg}}\approx5.48\frac{m}{s}
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The correct answers are:

(1) 6, 11, 16, 21, 26 (Option B)

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(1) Given Sequence:

a_n = 5n + 1

Now in order to find the first 5 terms, we need to put n=1,2,3,4,5 in the above sequence and solve.

For n=1: a_1 = 5(1) + 1 = 6

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For n=3: a_3 = 5(3) + 1 = 16

For n=4: a_4 = 5(4) + 1 = 21

For n=5: a_5 = 5(5) + 1 = 26

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8, 6, 4, 2, …

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a_n = a_{n-1} - d --- (1)

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d = difference between two consecutive numbers = 8-6 = 2

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a_2 = a_{2-1} - 2

a_2 = a_{1} - 2

Since a_1 = 8, therefore,

a_2 = 8 - 2 = 6 (correct)

Hence the correct answer is a_1 = 8; ~a_n = a_{n-1} - 2~ (Option A)

(3) Given Sequence:

−2, 1, 4, 7, …

To find the explicit definition, use the following formula:

a_n = a_1 + (n-1)*d --- (X)

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a_n = nth~term~of~the~sequence \\a_1 = 1st~term~of~the~sequence = -2 \\d = common~difference = 4-1 = 7-4 = 3 \\n = index~of~a~number~in~a~sequence \\

Plug in the values in (X):

(X)=> a_n = -2 + (n-1)*3~~~~ (Option D)

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