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Nana76 [90]
3 years ago
7

An 8-sided fair die is rolled twice and the product of the two numbers obtained when the die is rolled two times is calculated.

(A) Draw the possibility diagram of the product of the two numbers appearing on the die in each throw
Mathematics
1 answer:
Mumz [18]3 years ago
8 0

Answer:

See below

Step-by-step explanation:

When you roll an 8-sided die twice, the sample space is the set of all possible pairs (x,y) where x is the first outcome and y is the second outcome.

The sample space is:

[(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),(1, 7),(1, 8)\\(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6),(2, 7),(2, 8)\\(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6),(3, 7),(3, 8)\\(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6),(4, 7),(4, 8)\\(5, 1), (5, 2), (5, 3), (5, 4), (5, 5),(5, 6),(5, 7),(5, 8)\\(6, 1), (6, 2), (6, 3), (6, 4)(6, 5),(6, 6),(6, 7),(6, 8)\\(7, 1), (7, 2), (7, 3), (7, 4)(7, 5),(7, 6),(7, 7),(7, 8)\\(8, 1), (8, 2), (8, 3), (8, 4)(8, 5),(8, 6),(8, 7),(8, 8)]

The sample space of the product xy of each outcome forms the required possibility diagram.

This is given as:

1, 2, 3, 4, 5, 6,7,8\\2, 4, 6, 8, 10, 12,14,16\\3,6,9,12,15,18,21,24\\4,8,12,16,20,24,28,32\\5,10,15,20,25,30,35,40\\6,12,18,24,30,36,42,48\\7,14,21,28,35,42,49,56\\8,16,24,32,40,48,56,64

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This season, the probability that the Yankees will win a game is 0.61 and the
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The probability that the Yankees will lose when they score fewer than 5 runs is 17.16%.

<h3><u>Probability </u></h3>

Given that this season, the probability that the Yankees will win a game is 0.61 and the probability that the Yankees will score 5 or more runs in a game is 0.56, and the probability that the Yankees win and score 5 or more runs is 0.44, to determine what is the probability that the Yankees will lose when they score fewer than 5 runs the following calculation must be made:

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