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maxonik [38]
3 years ago
7

Amanda rides her bike east for 10 km. Angela rides her bike 20 degrees south of east 12 km. How far apart are they? Round to the

nearest tenth
Mathematics
1 answer:
Arada [10]3 years ago
6 0

Answer:

4.3\ km

Step-by-step explanation:

we know that

Applying the law of cosines

c^{2}=a^{2}+b^{2}-2(a)(b)cos(C)

we have

c-----> is the distance between Amanda and Angela

a=10\ km

b=12\ km

C=20\°

substitute the values

c^{2}=10^{2}+12^{2}-2(10)(12)cos(20\°)

c^{2}=18.4738

c=4.3\ km

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Step-by-step explanation: Please refer to the diagram attached.

The question gives us two parallel lines x and y as shown in the attachment. Then both parallel lines are cut by a transversal line w.

The transversal eventually results in four angle being formed at each point of intersection, both in line x and in line y. In line x, the angles formed are given as angles, 2, 4, 3 and 1. In line y, the angles formed are 6, 8, 7 and 5.

It is important to note that with the inclusion of the transversal line w, there is a relationship between the angles. looking at line y, we have one of the angles measuring 123.5 degrees (angle 6). That means angle 8 is derived as follows;

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Note also that angle 5 is opposite angle 8 and opposite angles are equal. Therefore angle 5 equals 56.5 degrees as well.

Looking at line x, angle 1 is alternate to angle 8 (alternate interior angles are equal), therefore angle 1 equals 56.5 degrees also.

The diagram and the accompanying explanation shows that angle 1 measures 56.5°

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