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Contact [7]
3 years ago
7

What two values can d have if d squared=9?

Mathematics
1 answer:
liq [111]3 years ago
6 0

Answer:

3 and I'm not sure about the other one

Step-by-step explanation:

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Next, you take your coordinate points (x,y) (2,3) and substitute them in your equation.

So, you have y-3=2(x-2)

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Step-by-step explanation:

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The principal amount, $4200, earns 3.6% interest compounded monthly.
svlad2 [7]

Answer:

a)

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

b)

The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 4,200.00 at a rate of 3.6% per year  compounded 12 times per year  over 10 years is $5667.28.

Step-by-step explanation:

a. Write the function that represents the value of the account at any time, t.

The function that represents the value of the account at any time, t

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

where

P represents the principal amount

r represents Annual Rate

n represents the number of compounding periods per unit t, at the end of each period

t represents the time Involve

b) What will the value be after 10 years?

Given

The principal amount  P = $4200

Annual Rate r = 3.6% = 3.6/100 = 0.036

Compounded monthly = n = 12

Time Period = t

To Determine:

The total amount A = ?

Using the formula

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

substituting the values

A\:=\:4200\left(1\:+\:\frac{0.003}{12}\right)^{\left(12\right)\left(10\right)}

\:A\:=\:4200\left(1.0025\right)^{120}

A=5667.28 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 4,200.00 at a rate of 3.6% per year  compounded 12 times per year  over 10 years is $5667.28.

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