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mestny [16]
2 years ago
10

Quadratic equations: Factoring

Mathematics
1 answer:
stellarik [79]2 years ago
6 0
Remember
if ab=0, then assume that a and b equal 0

factor out common term
comon term in 6x^2 and 15x is 3x
3x(2x)+3x(5)=0
3x(2x+5)=0
set each to zero
3x=0
x=0

2x+5=0
2x=-5
x=-5/2


x=-5/2 and 0
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1/3y+1/4=5/12 i need 20 character
lys-0071 [83]
Y/3 + 1/4 = 5/12
4y/12 + 3/12 = 5/12
           4y/12 = 2/12
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                /4     /4
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Therefore y = 1/2

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Step-by-step explanation:

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Consider the sequence of numbers: 3/8, 3/4, 1 /18, 1 1/2, 1 7/8
vredina [299]

Question:

Consider the sequence of numbers: \frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}

Which statement is a description of the sequence?

(A) The sequence is recursive, where each term is 1/4 greater than its preceding term.

(B) The sequence is recursive and can be represented by the function

f(n + 1) = f(n) + 3/8 .

(C) The sequence is arithmetic, where each pair of terms has a constant difference of 3/4 .

(D) The sequence is arithmetic and can be represented by the function

f(n + 1) = f(n)3/8.

Answer:

Option B:

The sequence is recursive and can be represented by the function

f(n + 1) = f(n) + \frac{3}{8}  .

Explanation:

A sequence of numbers are

\frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}

Let us first change mixed fraction into improper fraction.

\frac{3}{8}, \frac{3}{4}, \frac{9}{8}, \frac{3}{2}, \frac{15}{8}

To find the pattern of the sequence.

To find the common difference between the sequence of numbers.

\frac{3}{4}-\frac{3}{8}=\frac{6}{8}-\frac{3}{8}= \frac{3}{8}

\frac{9}{8}-\frac{3}{4}=\frac{9}{8}-\frac{6}{8}= \frac{3}{8}

\frac{3}{2}-\frac{9}{8}=\frac{12}{8}-\frac{9}{8}= \frac{3}{8}

\frac{15}{8}-\frac{3}{2}=\frac{15}{8}-\frac{12}{8}= \frac{3}{8}

Therefore, the common difference of the sequence is 3.

That means each term is obtained by adding \frac{3}{8} to the previous term.

Hence, the sequence is recursive and can be represented by the function f(n + 1) = f(n) + \frac{3}{8}  .

3 0
2 years ago
You buy a new car for $31,300. The average car depreciates in value by 14% per year. How much will it be worth after each of the
Andrei [34K]

A = P(1 + rt)

A=31,300(1+.14*1)

A=35682

5 0
2 years ago
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