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erastova [34]
4 years ago
10

On the packaging for a triangular sail, the edge measurements for the sail are listed as 7 ft × 15 ft × 17 ft. Without unfurling

the sail, you want to determine if the sail forms a right triangle, an acute triangle, or an obtuse triangle. Using the tools from this lesson, you determine that the general shape of the sail is a(n)______ triangle.
Mathematics
2 answers:
riadik2000 [5.3K]4 years ago
8 0
The triangle is obtuse since the sum of the squares of 2 sides are greater than the square of the third side. (Converse Pythagorean theorem) Hope this helps!
Natalka [10]4 years ago
5 0

Answer:

Shape of Triangular sail is Obtuse Angled Triangle.

Step-by-step explanation:

Given: Length of sides of triangular sail = 7 ft , 15 ft , 7 ft

To find: Shape of Sail .i.e., shape of triangle

We use a result which states that

if a , b  , c are sides of triangle where c is greater then a & b.

now, if c² < a² + b² then triangle is Acute angled

if c² = a² + b² then triangle is Right angled

if c² > a² + b² then triangle is Obtuse angled

here a = 7 , b = 7 &  c = 15

c² = 15² = 225

a² + b² = 7² + 7² = 49 + 49 = 98

since, c² > a² + b²

⇒ Triangle must be Obtuse Angled.

Therefore, Shape of Triangular sail is Obtuse Angled Triangle.

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If a number a is chosen at random from the set
Ivanshal [37]

Answer:

D. 3/19

Step-by-step explanation:

12/1 = 12

12/2 = 6

12/3 = 4

These are the only ones that make the equation true.

There are also only 19 numbers because they need to be less than 20 like the question indicated. Therefore, the answer is D.

5 0
3 years ago
A short-wave radio antenna is supported by two guy wires, 150 ft and 180 ft long. Each wire is attached to the top of the antenn
Dafna1 [17]

The distance between the anchor points of the two guy wires holding radio antenna is 181 feet (to the nearest foot)

<h3>How to determine the distance between the two anchor points of the guy wire</h3>

The problem will be solved using SOH CAH TOA

let the distance between the 150 ft long guy wire and the radio antenna be x

let the distance between the 180 ft long guy wire and the radio antenna be y

cos 65° = x / 150

x = cos 65° * 150

x = 63.39 ft

The height of the antenna

sin 65° = height of antenna / 150

height of antenna = sin 65 * 150

height of antenna = 135.95

using Pythagoras theorem

(length of guy wire)² = (height of the antenna)² + (anchor distance)²

(anchor distance)² = 180² - 135.95²

anchor distance = √(180² - 135.95²)

anchor distance = 117.97

The anchor points distance apart

= 63.39 + 117.97

= 181 (to the nearest foot)

Learn more on Pythagoras theorem here:

brainly.com/question/29241066

#SPJ1

4 0
2 years ago
5x/x^2-9 + 7/x+3<br> Simplify
rjkz [21]

5x ÷ x² - 9 + 7 ÷ x + 3

Write the division as a fraction:

\frac{5x}{x^{2} }\\ - 9 + \frac{7}{x} + 3

Simplify the expression:

\frac{5}{x} - 9 + \frac{7}{x} + 3

Calculate the sum:

\frac{5}{x} - 6 + \frac{7}{x}

Write all numerators above the common denominator:

\frac{5 - 6x + 7}{x}

Add the numbers and you get the final answer:

\frac{12-6x}{x}

4 0
3 years ago
A patio has an area of 1420 square feet. If the length is 45 1/2, what is the width​
Anni [7]

[ Answer ]

\boxed{Width \ = \ 31\frac{19}{91} \ Ft^{2}}

[ Explanation ]

Area = 1420

Width = 45\frac{1}{2}

Area For Rectangle: Length · Width

Use division to find width:

1420 ÷ 45\frac{1}{2}

Convert mixed numbers to fractions:

1420 = \frac{1420}{1}

45\frac{1}{2} = \frac{91}{2}

\frac{1420}{1} ÷ \frac{91}{2}

Use mixed multiplication:

\frac{1420*2}{1*91}

= \frac{2140}{91}

Simplify:

= 31\frac{19}{91}

\boxed{[ \ Eclipsed \ ]}

7 0
3 years ago
What is the slope (2,10) (5,9)
Sergeeva-Olga [200]

Answer:

slope=(9-10)/(5-2)=-1/3

5 0
3 years ago
Read 2 more answers
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