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Triss [41]
4 years ago
6

What positive number is twice it's own square

Mathematics
2 answers:
LekaFEV [45]4 years ago
8 0
The answer is 4. The square root of 4 is equal to 2, and 4 is twice the amount of 2. Therefore, the answer is 4.
ycow [4]4 years ago
4 0

Answer:  The positive number is  \dfrac{1}{2}.

Step-by-step explanation:  We are given to find the positive number that is twice it's own square.

Let x denotes the required number.

Then, according to the given information, we have

x=2x^2\\\\\Rightarrow 2x^2-x=0\\\\\Rightarrow x(2x-1)=0\\\\\Rightarrow x=0,~~2x-1=0\\\\\Rightarrow x=0,~\dfrac{1}{2}.

Sine 0 is not considered as a positive number, so the required positive number is \dfrac{1}{2}.

Thus, the positive number is \dfrac{1}{2}.

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I think it is the 1st quadrant, because both numbers are positive.

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Solve system by elimination<br> y=x^2<br> y=x+2<br> SHOW YOUR WORK
Dimas [21]
We have that
y=x²----> equation 1<span>
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multiply equation 1 by -1
-y=-x</span>²

add equation 1 and equation 2
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------------
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Group terms that contain the same variable, and move the constant to the opposite side of the equation

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<span>Complete the square. Remember to balance the equation by adding the same constants to each side
</span>(x²-x+0.5²)=2+0.5²

Rewrite as perfect squares

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for x=2
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for x=-1
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the point is (-1,1)

the answer is
the solution of the system are the points
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3 0
4 years ago
Fractions in simplest form that have denominators of 2,
Montano1993 [528]

One of the fractions could be 1/2

Hoped this helped at all :)

8 0
3 years ago
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