Question

What positive number is twice it's own square

Answer 1

The answer is 4. The square root of 4 is equal to 2, and 4 is twice the amount of 2. Therefore, the answer is 4.

Answer 2

Answer:  The positive number is  $\dfrac{1}{2}.$

Step-by-step explanation:  We are given to find the positive number that is twice it's own square.

Let x denotes the required number.

Then, according to the given information, we have

$x=2x^2\\\\\Rightarrow 2x^2-x=0\\\\\Rightarrow x(2x-1)=0\\\\\Rightarrow x=0,~~2x-1=0\\\\\Rightarrow x=0,~\dfrac{1}{2}.$

Sine 0 is not considered as a positive number, so the required positive number is $\dfrac{1}{2}.$

Thus, the positive number is $\dfrac{1}{2}.$