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3 years ago

Number 7 I need help please?!!!

Mathematics

1 answer:

Genrish500 [490]3 years ago

3 0

Answer:

I think it is the 1st quadrant

Step-by-step explanation:

I think it is the 1st quadrant, because both numbers are positive.

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WOULD YOU RATHER...

8090 [49]

Answer:

0.015 km/s

Step-by-step explanation:

40 km/hr

0.015 km/s

0.015 ÷ (1/3600)

0.015 × 3600

= 54 km/hr

7 0

3 years ago

Read 2 more answers

Find the absolute maximum and absolute minimum values of the function f(x, y) = x 2 + y 2 − x 2 y + 7 on the set d = {(x, y) : |

dsp73

Looks like $f(x,y)=x^2+y^2-x^2y+7$ .

$f_x=2x-2xy=0\implies2x(1-y)=0\implies x=0\text{ or }y=1$

$f_y=2y-x^2=0\implies2y=x^2$

If $x=0$ , then $y=0$ - critical point at (0, 0).
If $y=1$ , then $x=\pm\sqrt2$ - two critical points at $(-\sqrt2,1)$ and $(\sqrt2,1)$

The latter two critical points occur outside of $D$ since $|\pm\sqrt2|>1$ so we ignore those points.

The Hessian matrix for this function is

$H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}2-2y&-2x\\-2x&2\end{bmatrix}$

The value of its determinant at (0, 0) is $\det H(0,0)=4>0$ , which means a minimum occurs at the point, and we have $f(0,0)=7$ .

Now consider each boundary:

If $x=1$ , then

$f(1,y)=8-y+y^2=\left(y-\dfrac12\right)^2+\dfrac{31}4$

which has 3 extreme values over the interval $-1\le y\le1$ of 31/4 = 7.75 at the point (1, 1/2); 8 at (1, 1); and 10 at (1, -1).

If $x=-1$ , then

$f(-1,y)=8-y+y^2$

and we get the same extrema as in the previous case: 8 at (-1, 1), and 10 at (-1, -1).

If $y=1$ , then

$f(x,1)=8$

which doesn't tell us about anything we don't already know (namely that 8 is an extreme value).

If $y=-1$ , then

$f(x,-1)=2x^2+8$

which has 3 extreme values, but the previous cases already include them.

Hence $f(x,y)$ has absolute maxima of 10 at the points (1, -1) and (-1, -1) and an absolute minimum of 0 at (0, 0).

3 0

3 years ago

A parabola has a vertex of (5,4) and goes through the point (6,-10)

natali 33 [55]

Y = -2(x-5)^2 + 4

Note: vertex form is 0, f(x), y, or nothing= a(x-h)^2 + k
The opposite of the x value of the vertex is h
The y value value of the vertex is k.

Find a. Plug in (6,-10)

-10 = a(6-5)^2 + 4
-10 = 1a + 4
-10 = 5a
a = -2

5 0

3 years ago

Find the area of the polygon XYZ that has its vertices at X(–3, 6), Y(–3, 1), and Z(5, 1).

elixir [45]

Hope you can understand

6 0

3 years ago

42.6 is 66 2/3% of what number?

Elza [17]

42.6 is 66 2/3% of 63.9

the answer is : 63.9

4 0

3 years ago