The simplification of the given algebraic expression is;
yz = (z + 1)/z(z - 1)
<h3>How to simplify algebraic expressions?</h3>
We are given y left parenthesis z right parenthesis which is expressed as; yz
Now, we are given the algebraic expression that yz equals space fraction numerator z squared minus 1 over denominator z left parenthesis z minus 1 right parenthesis squared end fraction
z squared minus 1 over denominator z left parenthesis z minus 1 right parenthesis squared end fraction is expressed as; (z² - 1)/z(z - 1)²
Thus, our main expression is;
yz = (z² - 1)/z(z - 1)²
Factorizing the numerator and denominator gives;
yz = (z + 1)(z - 1)/z(z - 1)(z - 1)
(z - 1) is common to both numerator and denominator and as such, we now have;
yz = (z + 1)/z(z - 1)
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Answer:
Continuously
Step-by-step explanation:
Continuously
Answer:
y=x-1
Step-by-step explanation:
Answer:
-5
Step-by-step explanation:
Answer:
See Below.
Step-by-step explanation:
By the Factor Theorem, if we divide <em>q(x)</em> into <em>p(x) </em>and the resulting remainder is 0, then <em>p(x)</em> is divisible by <em>q(x)</em> (i.e. there are no remainders).
Problem 1)
We are given:

We should find the remainder when dividing <em>p(x)</em> and <em>q(x)</em>. We can use the Polynomial Remainder Theorem. When dividing a polynomial <em>p(x)</em> by a binomial in the form of (<em>x</em> - <em>a</em>), then the remainder will be <em>p(a).</em>
Here, our divisor is (<em>x</em> + 1) or (<em>x</em> - (-1)). So, <em>a </em>= -1.
Then by the Polynomial Remainder Theorem, the remainder when performing <em>p(x)/q(x)</em> is:

The remainder is 0, satisfying the Factor Theorem. <em>p(x)</em> is indeed divisible by <em>q(x)</em>.
Problem 2)
We are given:

Again, use the PRT. In this case, <em>a</em> = 3. So:

It satisfies the Factor Theorem.
Problem 3)
We are given:

Use the PRT. In this case, <em>a</em> = 10. So:

It satisfies the Factor Theorem.
Since all three cases satisfy the Factor Theorem, <em>p(x)</em> is divisible by <em>q(x)</em> in all three instances.