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exis [7]
3 years ago
9

A class of 12 girls and 14 boys is going to choose 3 students to represent them in student government. Allie suggested that the

first 3 students to arrive in class the next day should be the representatives. Bobby suggested that each student roll 2 numbers cubes and the 3 students with the highest sum should be the representatives. Whose method would result in a fair sample that represents the class population, and why?.
Mathematics
2 answers:
Vikki [24]3 years ago
8 0
<h2>Answer:</h2>

The method suggested by Bobby is better than Allie.

<h2>Step-by-step explanation:</h2>

A fair sample is a sample where each sample has an equal opportunity to get selected for any survey.

Here, in the given question, Allie suggested that the first 3 students to arrive in class the next day should be the representatives. This sample is not random or fair.

Whereas, Bobby suggested that each student roll 2 numbers cubes and the 3 students with the highest sum should be the representatives. This method is a fair method.

The method suggested by Bobby is better than Allie as every student will get an equal chance to perform and also has an equal chance to win and get a high sum.

ipn [44]3 years ago
4 0

Answer:

Bobby, because every student has an equal chance to get a high sum

Explanation:

Allie suggesting that the first 3 students to arrive in class the next day should be the representatives would not result in a fair sample because not everyone would have the chance to get to school early enough.Bobby suggesting that each student roll 2 numbers cubes and the 3 students with the highest sum should be the representatives would result in a fair sample because everyone would get a chance to roll the number cubes.

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There are 5 boys in the eighth grade class and 9 girls . If mr. Jowers randomly selects one student to carry the Eagle folder ,
Valentin [98]

Answer: 36.78% chance

Step-by-step explanation: Add 9+5 and divide 5 to 14

7 0
3 years ago
I need to know ASAP! Thanks ^^
jek_recluse [69]

Answer:

PQ=30

Step-by-step explanation:

Knowing that the segment has 3 parts that are 3:1:1 and sum up to 50, you could find how much 1 would equal by finding the total in relation to the ratio (doing 3+1+1) which gets you 5 parts. Then you can divide the total (50) by 5 to figure out how much one part would equal (10). Now, since you know that 1 part is equal to 10 and that PQ is 3 parts, you can find that PQ is equal to 3x10, or 30.

7 0
3 years ago
What is y=4x^2-9x+1 in vertex form
Anna11 [10]

Answer:

y = 4 \left(x - \dfrac{9}{8} \right)^2 - \dfrac{65}{16}

Step-by-step explanation:

y = 4x^2 - 9x + 1

You need to complete the square on the right side.

y = (4x^2 - 9x) + 1

y = 4(x^2 - \dfrac{9}{4}x) + 1

y = 4 \left( x^2 - \dfrac{9}{4}x + \left( \dfrac{9}{8} \right)^2 \right) + 1 - 4\left( \dfrac{9}{8} \right)^2

y = 4 \left(x - \dfrac{9}{8} \right)^2 + 1 - 4 \left( \dfrac{81}{64} \right)

y = 4 \left(x - \dfrac{9}{8} \right)^2 + 1 - \dfrac{81}{16}

y = 4 \left(x - \dfrac{9}{8} \right)^2 + \dfrac{16}{16} - \dfrac{81}{16}

y = 4 \left(x - \dfrac{9}{8} \right)^2 - \dfrac{65}{16}

3 0
3 years ago
It is estimated that 75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell
Mademuasel [1]

Answer:

a) 75

b) 4.33

c) 0.75

d) 3.2 \times 10^{-13} probability that no one in a simple random sample of 100 young adults owns a landline

e) 6.2 \times 10^{-61} probability that everyone in a simple random sample of 100 young adults owns a landline.

f) Binomial, with n = 100, p = 0.75

g) 4.5 \times 10^{-8} probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

Step-by-step explanation:

For each young adult, there are only two possible outcomes. Either they do not own a landline, or they do. The probability of an young adult not having a landline is independent of any other adult, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

75% of all young adults between the ages of 18-35 do not have a landline in their homes and only use a cell phone at home.

This means that p = 0.75

(a) On average, how many young adults do not own a landline in a random sample of 100?

Sample of 100, so n = 100

E(X) = np = 100(0.75) = 75

(b) What is the standard deviation of probability of young adults who do not own a landline in a simple random sample of 100?

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{100(0.75)(0.25)} = 4.33

(c) What is the proportion of young adults who do not own a landline?

The estimation, of 75% = 0.75.

(d) What is the probability that no one in a simple random sample of 100 young adults owns a landline?

This is P(X = 100), that is, all do not own. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 100) = C_{100,100}.(0.75)^{100}.(0.25)^{0} = 3.2 \times 10^{-13}

3.2 \times 10^{-13} probability that no one in a simple random sample of 100 young adults owns a landline.

(e) What is the probability that everyone in a simple random sample of 100 young adults owns a landline?

This is P(X = 0), that is, all own. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{100,0}.(0.75)^{0}.(0.25)^{100} = 6.2 \times 10^{-61}

6.2 \times 10^{-61} probability that everyone in a simple random sample of 100 young adults owns a landline.

(f) What is the distribution of the number of young adults in a sample of 100 who do not own a landline?

Binomial, with n = 100, p = 0.75

(g) What is the probability that exactly half the young adults in a simple random sample of 100 do not own a landline?

This is P(X = 50). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 50) = C_{100,50}.(0.75)^{50}.(0.25)^{50} = 4.5 \times 10^{-8}

4.5 \times 10^{-8} probability that exactly half the young adults in a simple random sample of 100 do not own a landline.

8 0
3 years ago
Marcus earns $8.40 per hour. He works for 26 hours each week, 48 weeks each year. If he earns over $10,000, then Marcus has to p
MAVERICK [17]

We have been given that Marcus works for 26 hours each week and 48 weeks each year.

Thus in a year he works for 26 \times 48 = 1248 hours.

Now, we have been given that Marcus earns $8.40 per hour.

Therefore, in 1248 hours, he earns

1248 \times 8.40\\&#10;\\&#10;=\$ 10483.2

Marcus has to pay tax if he earns more than $10,000. Now we have calculated that he earns $ 10483.2  which is higher than $10,000.

Therefore, Marcus has to to pat tax.

6 0
3 years ago
Read 2 more answers
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