The test statistic for the hypothesis would be 1.413.
Given that the participants in its new diet program lose, on average, more than 13 pounds and the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds.
The objective is to text the advertisement's claim that participants in new diet program lose weight, on average, more than 13 pounds.
Hypothesis:
Null hypothesis:H₀:μ=13
Alternative hypothesis:Hₐ:μ>13
Here, μ be the mean weight loss of all participants.
n=30,
Degree of freedom n-1=30-1=29
=13.8 and s=3.1
To test the null hypothesis H₀, the value of test static would be calculated as follows:

Hence, the value of the test static for the hypothesis with the mean weight loss of these participants as 13.8 pounds with a standard deviation of 3.1 pounds is 1.413.
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Answer:
1)5873 x 4=23492
2)5000 x 4=20000
3)800 x 4=3200
4)70 x 4=280
5)3 x 4=12
Step-by-step explanation:
The answer is 168 logs.
1st row: 15 logs
2nd row: 18 logs
3rd row: 21 logs
(so, each row has 3 more logs)
4th row: 24 logs
5th row: 27 logs
6th row: 30 logs
7th row: 33 logs
The sum of logs from each row is: 15 + 18 + 21 + 24 + 27 + 30 + 33 = 168 logs
Answer:
c. 25 minutes
Step-by-step explanation:
3x + 10 = 85
3x = 85 - 10
3x = 75
x = 25
Travel direction 3i + 2j, slope = 2/3.
We have slope and a point (-2,1) this gives us a line equation:
LINE BEFORE THE TURN, EQUATION: y = (2/3)x + 1
The point of intersection of the two lines:
1) through (-2,1) with slope 2/3 and;
2) through (-1,6) with slope 3/2.