All categories

3 years ago

Can someone please help? I’m not very good with cubes. Thanks!

Mathematics

2 answers:

goblinko [34]3 years ago

8 0

Answer:

green with yellow

orange with purple

blue with brown

Step-by-step explanation:

Whitepunk [10]3 years ago

3 0

The bottom left square goes to the right middle square

The left middle square goes to the bottom right square

And the Top left square goes to the top right square

Its a little tricky but I hope it's right and it helps!!

You might be interested in

The question is in the picture. (Alegbra 1)

morpeh [17]

Answer:

Step-by-step explanation:

4/5a*3/2a^2

4*3/5a*2a^2

12/10a^3

6/5a^3

therefore ur answer is 6/5a^3

6 0

3 years ago

Read 2 more answers

Show work please<br> \sqrt(x+12)-\sqrt(2x+1)=1

Nesterboy [21]

Answer:

$x=4$

Step-by-step explanation:

Given $\displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1$ , start by squaring both sides to work towards isolating $x$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2$

Recall $(a-b)^2=a^2-2ab+b^2$ and $\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1$

Isolate the radical:

$\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}$

Square both sides:

$\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2$

Expand using FOIL and $(a+b)^2=a^2+2ab+b^2$ :

$\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36$

Move everything to one side to get a quadratic:

$\displaystyle-\frac{1}{4}x^2+7x-24=0$

Solving using the quadratic formula:

A quadratic in $ax^2+bx+c$ has real solutions $\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ . In $\displaystyle-\frac{1}{4}x^2+7x-24$ , assign values:

$\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24$

Solving yields:

$\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}$

Only $x=4$ works when plugged in the original equation. Therefore, $x=24$ is extraneous and the only solution is $\boxed{x=4}$

4 0

2 years ago

The figure shows the location of 3 points around a lake. The length of the lake, BC, is also shown.

lions [1.4K]

Answer:

5.29

Step-by-step explanation:

Pythagorean theorem is used

We will call AB x

x^2 + 6^2 = 8^2

x^2 + 36 = 64

x^2 = 28

x = 5.2915026

4 0

3 years ago

How to find the area of a triangle with a base of 32ft

Sergeu [11.5K]

Well to find the area of any figure you must first have knowledge on the formula. The formula for a triangle is 1/2 x b x h. Since you have the base 32, multiply that by 1/2 which will give you 16. Then you have to multiply 16 by the height. I'm not sure what the height is because you never gave me one but hopefully this helped! God bless :)

4 0

3 years ago

What are the vertex focus and directrix of a parabola with equation x=y^2+14y-2

zimovet [89]

This is a sideways opening parabola, opening to the right to be more specific, since the leading coefficient is a positive 1. The rule for a focus and a directrix is that they are the same number of units from the vertex (in other words, the vertex is dead center between them), and that the vertex is on the same axis that the focus is. We need to find the vertex then to determine what the focus and the directrix are. We will complete the square on that to find the vertex. Begin by setting it equal to 0, then move the 2 over by addition to get $y^2+14y=2$ . Now we will complete the square on the y terms. Take half the linear term, square it, and add it to both sides. Our linear term is 14. Half of 14 is 7, and 7 squared is 49. So we add 49 to both sides. $y^2+14y+49=2+49$ , which of course simplifies to $y^2+14y+49=51$ . The purpose of this is to find the k coodinate of the vertex which will be revealed when we write the perfect square binomial we created during this process: $(y+7)^2=51$ . Moving the 51 back over by subtraction gives us $(y+7)^2-51=x$ . The vertex then is (-51,-7). The formula to find the focus using this vertex is $(h+ \frac{1}{4a},k)$ . As I stated quite a while ago, the leading coefficient on our parabola was a +1 so our "a" value is 1, and the focus is then found in $(-51+ \frac{1}{4},-7)$ which simplifies to $(-50.75, -7)$ . If the vertex is (-51, -7) and the focus is (-50.75, -7), then the distance between them is 1/4, or .25. That means that the directrix is also .25 units from the vertex, but in the other direction. Our directrix is a vertical line, and it will have the equaion x = -51.25. Summing up, your focus is (-50.75, -7) and your directrix is x = -51.25

7 0

3 years ago