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3 years ago

Can someone please help? I’m not very good with cubes. Thanks!

Mathematics

2 answers:

goblinko [34]3 years ago

8 0

Answer:

green with yellow

orange with purple

blue with brown

Step-by-step explanation:

Whitepunk [10]3 years ago

3 0

The bottom left square goes to the right middle square

The left middle square goes to the bottom right square

And the Top left square goes to the top right square

Its a little tricky but I hope it's right and it helps!!

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P(S) = 5/8<br> P(T) = 1/8<br> If S and T are mutually exclusive events, find P(S or T),

Aleks04 [339]

Answer:

P(S ∪ T) = 3/4

Step-by-step explanation:

Given:

P(S) = 5/8
P(T) = 1/8

For mutually exclusive events S and T,

P(S ∪ T) = P(S) + P(T)

Therefore,

P(S ∪ T) = (5/8) + (1/8)

= 6/8

= 3/4

6 0

2 years ago

What does the mode mean in math?

bogdanovich [222]

Answer: The number which appears most often in a set of numbers. Example: in {6, 3, 9, 6, 6, 5, 9, 3} the Mode is 6 (it occurs most often)

Step-by-step explanation: PLease give me brainlest

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3 years ago

A publisher reports that 45% of their readers own a laptop. A marketing executive wants to test the claim that the percentage is

nexus9112 [7]

Answer:

$z=\frac{0.40 -0.45}{\sqrt{\frac{0.45(1-0.45)}{370}}}=-1.933$

$p_v =2*P(z$

Step-by-step explanation:

Information given

n=370 represent the sample selected

$\hat p=0.4$ estimated proportion of readers owned a laptop

$p_o=0.45$ is the value that we want to test

z would represent the statistic

$p_v$ represent the p value

Creating the hypothesis

We need to conduct a hypothesis in order to test if the true proportion of readers owned a laptop is different from 0.45, the system of hypothesis are:

Null hypothesis: $p=0.45$

Alternative hypothesis: $p \neq 0.45$

The statistic is:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing we got:

$z=\frac{0.40 -0.45}{\sqrt{\frac{0.45(1-0.45)}{370}}}=-1.933$

Calculating the p value

We have a bilateral test so then the p value would be:

$p_v =2*P(z$

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3 years ago

The given data set shows the weight, in pounds, of nine dogs at an animal hospital.

otez555 [7]

The data value 110 would be considered an outlier, all of the numbers are within the range 20 to 40.

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Arlecino [84]

It would be the first one because each orange costs $0.34

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3 years ago

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