![\mathbf J=\begin{bmatrix}\dfrac{\partial x}{\partial u}&\dfrac{\partial x}{\partial v}\\\\\dfrac{\partial y}{\partial u}&\dfrac{\partial y}{\partial v}\end{bmatrix}=\begin{bmatrix}2u+v&u\\v^2&2uv\end{bmatrix}](https://tex.z-dn.net/?f=%5Cmathbf%20J%3D%5Cbegin%7Bbmatrix%7D%5Cdfrac%7B%5Cpartial%20x%7D%7B%5Cpartial%20u%7D%26%5Cdfrac%7B%5Cpartial%20x%7D%7B%5Cpartial%20v%7D%5C%5C%5C%5C%5Cdfrac%7B%5Cpartial%20y%7D%7B%5Cpartial%20u%7D%26%5Cdfrac%7B%5Cpartial%20y%7D%7B%5Cpartial%20v%7D%5Cend%7Bbmatrix%7D%3D%5Cbegin%7Bbmatrix%7D2u%2Bv%26u%5C%5Cv%5E2%262uv%5Cend%7Bbmatrix%7D)
The Jacobian has determinant
Answer:
Step-by-step explanation:
Answer:
a. Andrea is incorrect
b. By solving for x, we find that x does not equal 8, but it is equal to 7.
Step-by-step explanation:
8+4=2(x-1)
8+4=2x-2
12=2x-2
14=2x
x=7
C is the answer you are looking for.