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Evgen [1.6K]
3 years ago
13

What is the value of the expression -17 * 1.3 ​

Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0

Answer:

Step-by-step explanation:

if you multiply -17 by 1.3

-17*1.3=-22.10

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Please answer the following questions 1 2 and 3 with showing your work fully!
spayn [35]

Answer:

1. Point of intersection = (4, 360)

2. (4, 360) number of hours and the total cost of the repairs is the same for both repair shops

3. Amy's Auto Repair: $280

Step-by-step explanation:

1.  y = 100 + 65x    and    y = 40 + 80x

Equate the equations and solve for x:

y = y ⇒ 100 + 65x = 40 + 80x

subtract 65x from both sides ⇒ 100 = 40 + 15x

subtract 40 from both sides ⇒ 60 = 15x

divide both sides by 15 ⇒ 4 = x

Therefore, x = 4

Substitute x = 4 into either of the equations to find y:

⇒ y = 40 + (80 x 4) = 40 + 320 = 360

Point of intersection = (4, 360)

2. The two lines intersect at (4, 360)

In this context, the point of intersection is where the number of hours and the total cost of the repairs is the same for both repair shops.

3. Substitute x = 3 into the equations and compare:

Mike's repair shop:  y = 100 + (65 x 3) = 295

Amy's auto repair: y = 40 + (80 x 3) = 280

Therefore, Amy's Auto Repair is the cheapest (as 280 < 295) and the cost is $280.

5 0
3 years ago
A 4 meter long ladder leans against a 90 degree wall at a 68 degree angle.
Alenkinab [10]

Answer:

Step-by-step explanation:

We use trig to answer these questions:

sin x = opposite side of a triangle / hypotenuse

cos x = adjacent side / hypotenuse

Construct a right triangle with hypotenuse 4 m and lower angle 68 degrees.

The height of the top of the ladder  is then defined by:

sin 68 degrees = height / 4 m, which yields (4 m)(sin 68) = height =

3.71 m

and the distance of the bottom of the ladder from the wall as follows:

cos 68 degrees = horizontal distance / hypotenuse =

1.50 m

3 0
3 years ago
Nine and four thousand one hundred twelve ten-thousandths
navik [9.2K]
Please specify, are we multiplying, adding, dividing or subtracting? Or am I supposed to transform these into number form?
6 0
3 years ago
Exercise 2.1.47 Prove that ifA^-1 exists and AX=0 then X =0.
stepan [7]

Answer:

Step-by-step explanation:

If A^{-1} exist, then we have that A^{-1}\cdot A=1.

Therefore, in the case that AX=0, if we multiply both

terms in the equation by A^{-1}, then we have

A \cdot A^{-1}X=A^{-1}0

and so the equation tells us that

X=A\cdot A^{-1}X=A^{-1}0=0.

5 0
3 years ago
Can any one help me please
frutty [35]
<span>i think this is the answer....... -yx • (y2 - 15)

</span>
7 0
4 years ago
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