Answer:
I think she is incorrect she need to change all the fractions to the same denominators
Step-by-step explanation:
We are going to change all the fractions to 64
9/64 stays the same
5/32 multiply 2 then 10/64
1/16 multiply by 4 then 4/64
1/8 multiply by 8 then 8/64
Now we can order then
5/32 > 9/64 > 1/8 > 1/16 This is the right order
She was wrong.
Answer:
If EFGH is an isosceles trapezoid,
if
EH=4x-27+
FG=x%2B9+
EG=3y%2B19
FH=11y-21
then EH=FG and EG=FH
set up equations:
4x-27=x%2B9 .......solve for x
4x-x=27%2B9
3x=36
x=36%2F3
3y%2B19=11y-21.......solve for y
11%2B19=11y-3y
30=8y
y=30%2F8
y=15%2F4
y=3.75
so,x=12 and y=3.75
you can also check the length of equal sides and equal diagonals:
EH=4%2A12-27+=21
FG=12%2B9+=21
EG=3%283.75%29%2B19=30.25
FH=11%283.75%29-21=30.25x=12
Step-by-step explanation:
Answer:
the answer is: 
Step-by-step explanation:
We get the answer using Pitagoras.
so
Answer:
yes
Step-by-step explanation:
because the corresponding angles are congruent, the triangles are congruent through CPCTC. If two sides are congruent and an included angle, then the triangles are congruent through the SAS postulate. And if two sides and a non-included angle are congruent then the triangles are congruent through the AAS postulate. Any way of looking at this proves congruency through various postulates, therefore the trianlges are congruent.
