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hjlf
3 years ago
15

!!!!Do not respond with I don't know or anything but help with the answer just for the points!!!!! The average test score A of f

ive test scores t 1​, t 2​, t 3​, t 4​, and t 5 can be computed by the formula shown below.
A=t 1​+t 2​+t 3​+t 4​+t 5/(over)5

If a student has test scores of 88​, 71​, 80​, and 72​, what score does she need on the fifth test so that her​ five-test average is 76​?
Mathematics
1 answer:
zepelin [54]3 years ago
8 0

Answer:

69

Step-by-step explanation:

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Which arrangement for these numbers is from least to greatest?
laiz [17]

Answer: D) -5/6 < -3/5 < -4/7 < -4/9

Step-by-step explanation:

Since putting fractions from least to greatest by using negatives the number or fraction has to be closed to 0. -5/6 is the farthest from 0 so it'll be the least -4/9 is closes to 0 so -4/9 is the most.

8 0
3 years ago
Solve for n 19 + 10n = 7n - 20
kakasveta [241]

Answer:

n = -13

Step-by-step explanation:

19 + 10n = 7n - 20

Subtract 7n from each side

19 + 10n-7n = 7n-7n - 20

19+3n = -20

Subtract 19 from each side

19+3n -19 = -20-19

3n = -39

Divide each side by 3

3n/3 = -39/3

n = -13

7 0
3 years ago
Graph the line with the equation y = 5/6 x – 1.
Nimfa-mama [501]

Answer:

do you want me to answer the equation and graph it or only graph it?

Step-by-step explanation:

this is the graph to y=5/6x-1:

3 0
3 years ago
Dwight made double the number of baskets in the second half of the basketball game than in the first half. He made 5 baskets in
Anarel [89]

He made 10 baskets because yoh must double 5

5 0
3 years ago
The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between 0 and 8 m
rusak2 [61]

Answer:

0.59375

Step-by-step explanation:

In a uniform distribution the probability that the time t is greater than any given value, X, is:

P(t\geq X)=1-\frac{X}{b-a}

In this problem, the limits of the distribution are a = 0 and b = 8 minutes.

For X =3.25 minutes:

P(t\geq 3.25)=1-\frac{3.25}{8-0} \\P(t\geq 3.25)=0.59375

The probability that a randomly selected passenger has a waiting time greater than 3.25 minutes is 0.59375.

8 0
3 years ago
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