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gladu [14]
4 years ago
14

Suppose you are climbing a hill whose shape is given by the equation z = 1400 − 0.005x2 − 0.01y2, where x, y, and z are measured

in meters, and you are standing at a point with coordinates (100, 120, 1206). the positive x-axis points east and the positive y-axis points north. (a) if you walk due south, will you start to ascend or descend?
Mathematics
1 answer:
Anarel [89]4 years ago
5 0
Answer: You start to ascend

Explanation:

Since you are walking due south and the positive y-axis points north, the y-coordinate decreases.

Let 

y' = y-coordinate after walking due south
z' = z-coordinate (or the height) after walking due south

So, the point where you stand after walking due south has a coordinate of (100, y', z'). Moreover,

z' = 1,400 - 0.05(100)^2 - 0.01(y')^2
\\ \boxed{z' = 1350 - 0.01(y')^2}

Since the y-coordinate decreases after walking due south and z' = 1350 - 0.01(y')^2,

y'  \leq 120\\ \Rightarrow (y')^2 \leq 120^2 = 14,400\\ \Rightarrow -0.01(y')^2 \geq -0.01(14,400) = -144\\ \Rightarrow z' = 1,350 - 0.01(y')^2 \geq 1,350 - 0.01(14,400) = 1,206\\ \Rightarrow \boxed{z' \geq 1,206}

So, the height after walking due south exceeds 1,206 meters, which is the previous height before walking due south. Therefore, if you walk due south from point with coordinates (100, 120, 1206), you are ascending.
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Step-by-step explanation:

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3 years ago
Deondra has 57 m of fencing to build a three-sided fence around a rectangular plot of
Law Incorporation [45]

(L=17m and W=20m) and (L=40m and W=8.5m) are the possible dimensions (length and width) of the field given that the three sided fence has a length of 57m the area of the land is 340 square meters. This can be obtained by forming quadratic equation for the data.

 

<h3>Calculate the set of possible dimensions (length and width) of the field:</h3>

Let length be L and width be W.

Given that,

three sided fence has a length of 57m,

⇒ 2W + L = 57 m ⇒ L = 57 - 2W

the area of the land is 340 square meters

length × width = 340 ⇒ L × W = 340

(57 - 2W)W = 340

57W - 2W² = 340

2W² - 57W + 340 = 0

Solve for W using quadratic formula,

a = 2, b = -57, c = 340

W = (-b±√b²-4ac)/2a  

   = (57±√3249-2720)/4

   = (57±√529)/4

   = (57±23)/4

W = 20 m and W = 8.5 m  

For W=20, L=57-2(20) = 17

For W=8.5, L=57-2(8.5) = 40

Hence (L=17m and W=20m) and (L=40m and W=8.5m) are the possible dimensions (length and width) of the field given that the three sided fence has a length of 57m the area of the land is 340 square meters.

Learn more about quadratic equations:

brainly.com/question/5975436

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Maksim231197 [3]

Answer:

D. 79!

Step-by-step explanation:

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