From Newton’s Second Law of Motion, the force needed to accelerate a moving object of mass m at acceleration a is given by ;
F = ma
In this case, m = 5kg, a = 6m/s^2 and we want to find F
F = 5 x 6
F = 30N
Therefore, a force of 30N is needed to accelerate a 5kg object at 6m/s^2.
2^3 = 8
11/9 = 1.22
sqrt 5 = 2.24
sqrt 20 = 4.47
sqrt 11 = 3.32
least to greatest : 11/9, sqrt 5 , sqrt 11 , sqrt 20, 2^3
Answer:
y-intercept: (0, 5/2)
x-intercept: (5/3, 0)
Step-by-step explanation:
The y-intercept is found by setting x=0 and dividing by the coefficient of y.
0 +2y = 5
y = 5/2
The x-intercept is found by setting y=0 and dividing by the coefficient of x.
3x +0 = 5
x = 5/3
The intercepts are ...
y-intercept: (0, 5/2)
x-intercept: (5/3, 0)
Answer:
draw the diagram and multiply 5x20
It would be: 289*24/100 = 6936/100 = 69.36