Please work this out for me.

Mathematics

1 answer:

Artist 52 [7]3 years ago

8 0

ok we have given three function h(x) defined in certain limits.for the first function

x≤-2 and second function -2<x≤-2 and for third function x>2

to find h(-1) we have the limit -2<x≤-2 so we need to plug -1 in the function -(x+1)²+2= -(-1+1)²+2=0+2=2.

to find h(-2) we know that we have x≤-2 so we need to plug x=-2 in tghe equation (1/4)x+2=(1/4)(-2)+2=-1/2+2=3/4.

for h(0) we know that zero lies in the limit -2<x≤2 so we need to plug x=0 in equation -(x+1)²+2=-(0+1)²+2=-(1)+2=1.

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Leokris [45]

Since the triangle is a right triangle at point B, then line AB is perpendicular to line BC.
For perpendicular lines, the product of their slopes is -1.
Slope of AB = (5 - 0)/(2 - 5) = 5/-3 = -5/3
Slope of BC = (y - 5)/(7 - 2) = (y - 5)/5

-5/3(y - 5)/5 = -1
-5(y - 5)/15 = -1
-5(y - 5) = -15
y - 5 = 3
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Therefore, the y-coordinate of point C is 8.

4 0

3 years ago

!!!URGENT!!! Read Image Below.

KIM [24]

Answer:

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