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Artyom0805 [142]
3 years ago
9

Please work this out for me.

Mathematics
1 answer:
Artist 52 [7]3 years ago
8 0

ok we have given three function h(x) defined in certain limits.for the first function

x≤-2 and second function -2<x≤-2 and for third function x>2

to find h(-1) we have the limit -2<x≤-2 so we need to plug -1 in the function -(x+1)²+2= -(-1+1)²+2=0+2=2.

to find h(-2) we know that we have x≤-2 so we need to plug x=-2 in tghe equation (1/4)x+2=(1/4)(-2)+2=-1/2+2=3/4.

for h(0) we know that zero lies in the limit -2<x≤2 so we need to plug x=0 in equation -(x+1)²+2=-(0+1)²+2=-(1)+2=1.

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2 years ago
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Jlenok [28]

Answer:

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Step-by-step explanation:

From the question we are told that:

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Equation of Length

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4 0
3 years ago
Convert the polar representation of this complex number into its standard form z=4(cos150+isin150).
Katen [24]

Answer:

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Step-by-step explanation:

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7 0
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The sum of the squares of 3 consecutive positive integers is 116. What are the numbers?
Elza [17]
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Take a look at the attachment to see how I got that solution. 
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5 0
3 years ago
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Alex17521 [72]

(180-30)/2 would be the equation and the answer is 150/2

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