Question

Please work this out for me.

Answer 1

ok we have given three function h(x) defined in certain limits.for the first function

x≤-2 and second function -2<x≤-2 and for third function x>2

to find h(-1) we have the limit -2<x≤-2 so we need to plug -1 in the function -(x+1)²+2= -(-1+1)²+2=0+2=2.

to find h(-2) we know that we have x≤-2 so we need to plug x=-2 in tghe equation (1/4)x+2=(1/4)(-2)+2=-1/2+2=3/4.

for h(0) we know that zero lies in the limit -2<x≤2 so we need to plug x=0 in equation -(x+1)²+2=-(0+1)²+2=-(1)+2=1.