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denis23 [38]
3 years ago
15

One car costs $18,942.

Mathematics
2 answers:
inn [45]3 years ago
8 0

Answer:

28,130(B)

Step-by-step explanation:

So, this is just adding one car by a different car

Or could be looked at as:

18,942+9,188

So lets go from right to left, to find the answer

8+2=10

So we know the ones place is 0.

Next we have the tens place, 8+4+(ten from last number)=13

So know we got: 30.

This gets rid of answer A.

Next we have the hundreds place, 1+9+(hundred from last number) = 11

So know we got: 130

Next we have the thousands, which is 9+8+(thousand from last number) = 18

So now we have 8,130

Well, we already get our answer from this. Since it uliminates C and D, in addition to A. With only B left.

But if we go further:

Next we have the ten thousands, which is 1+(ten thousands from last number)=2

<u>So now we have 28,130</u>

<u>This is our answer</u>

Hope this helps! ;)

oksian1 [2.3K]3 years ago
7 0

Answer:

28,130

Step-by-step explanation:

18,942+9188=28,130

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The lengths of a rectangle have been measured to the nearest tenth of a centimetre they are 87.3cm and 51.8cm what is the upper
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Answer: Area (upper bound) = 4527.7056 cm²

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<u>Step-by-step explanation:</u>

The length and width of the rectangle have been ROUNDED to the nearest tenth. Let's calculate what their actual measurements could be:

LENGTH: rounded to 87.3,  actual is between 87.25 and 87.34

<em>87.25 is the lowest number it could be that would round it UP to 87.3</em>

<em>87.34 is the highest number it could be that would round DOWN to 87.3</em>

WIDTH: rounded to 51.8, actual is between 51.75 and 51.84

<em>51.75 is the lowest number it could be that would round it UP to 51.8</em>

<em>51.84 is the highest number it could be that would round DOWN to 51.8</em>

To find the Area of the upper bound, multiply the highest possible length and the highest possible width:

A = 87.34 × 51.84 = 4527.7056

To find the Perimeter of the lower bound, calculate the perimeter using the lowest possible length and the lowest possible width:

P = 2(87.25 + 51.75) = 278

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