Ask question

Ask question

All categories

3 years ago

8

A popular fast food restaurant sells, on average, 18 orders of fries every 3 minutes. Based on this information, how many orders

of fries does the restaurant sell in an hour?

1 answer:

Tatiana [17]3 years ago

7 0

360. Hope this helps.

You might be interested in

How many terms are in the expression shown below? 5u 3 v + 3u 2 v 2 + 4uv + 5

Marianna [84]

Answer:

There are four terms of the expression $5u^3v+3u^2v^2+4uv+5$ .

Step-by-step explanation:

The given expression is $5u^3v+3u^2v^2+4uv+5$ .

The first term of this expression is $5u^3v$ .

The second term of this expression is $3u^2v^2$ .

The third term of the expression is $4uv$ .

The fourth term of the expression is $5$ .

Therefore, there are four terms in the given expression.

7 0

3 years ago

The article "Students Increasingly Turn to Credit Cards" (San Luis Obispo Tribune, July 21, 2006) reported that 37% of college f

Sloan [31]

Answer:

Step-by-step explanation:

Hello!

There are two variables of interest:

X₁: number of college freshmen that carry a credit card balance.

n₁= 1000

p'₁= 0.37

X₂: number of college seniors that carry a credit card balance.

n₂= 1000

p'₂= 0.48

a. You need to construct a 90% CI for the proportion of freshmen who carry a credit card balance.

The formula for the interval is:

p'₁± $Z_{1-\alpha /2}*\sqrt{\frac{p'_1(1-p'_1)}{n_1} }$

$Z_{1-\alpha /2}= Z_{0.95}= 1.648$

0.37±1.648* $\sqrt{\frac{0.37*0.63}{1000} }$

0.37±1.648*0.015

[0.35;0.39]

With a confidence level of 90%, you'd expect that the interval [0.35;0.39] contains the proportion of college freshmen students that carry a credit card balance.

b. In this item, you have to estimate the proportion of senior students that carry a credit card balance. Since we work with the standard normal approximation and the same confidence level, the Z value is the same: 1.648

The formula for this interval is

p'₂± $Z_{1-\alpha /2}*\sqrt{\frac{p'_2(1-p'_2)}{n_2} }$

0.48±1.648* $\sqrt{\frac{0.48*0.52}{1000} }$

0.48±1.648*0.016

[0.45;0.51]

With a confidence level of 90%, you'd expect that the interval [0.45;0.51] contains the proportion of college seniors that carry a credit card balance.

c. The difference between the width two 90% confidence intervals is given by the standard deviation of each sample.

Freshmen: $\sqrt{\frac{p'_1(1-p'_1)}{n_1} } = \sqrt{\frac{0.37*0.63}{1000} } = 0.01527 = 0.015$

Seniors: $\sqrt{\frac{p'_2(1-p'_2)}{n_2} } = \sqrt{\frac{0.48*0.52}{1000} }= 0.01579 = 0.016$

The interval corresponding to the senior students has a greater standard deviation than the interval corresponding to the freshmen students, that is why the amplitude of its interval is greater.

8 0

3 years ago

Which angle forms a y-coordinate on a unit circle of /~3/2 (square root of 3 over 2)

mixer [17]

Answer:

$\theta=60\degree$

Or

$\theta=\frac{\pi}{3}$

Step-by-step explanation:

We want to find the angle which forms a y-coordinate of $\frac{\sqrt{3} }{2}$

on the unit circle.

The y-coordinate on the unit circle is given by $\sin(\theta)$ .

This implies that $\sin(\theta)=\frac{\sqrt{3} }{2}$

$\Rightarrow \theta=\sin^{-1}(\frac{\sqrt{3} }{2})$

$\Rightarrow \theta=\sin^{-1}(\frac{\sqrt{3} }{2})$

$\Rightarrow \theta=60\degree$

Or

$\theta=\frac{\pi}{3}$

3 0

3 years ago

MATHHHHHHHHHHHHHHHHHHHHHHHHA

Kruka [31]

Hello there!

|b| > 2

Solve for the absolute value

We know either b > 2 or b < -2

b > 2

b < -2

Thus,

The correct answer is option A

b < -2 or b > 2

7 0

3 years ago

If $5,000 is invested at 4% simple intrest for 30 years. what will be the total intrest earned in the 30 years?

vodka [1.7K]

Answer:$1.20

Step-by-step explanation: Find 4% of 30

I am using a calculator, but you can get the same result if you multiply .04 and 30

You should get 1.2 or $1.20

3 0

3 years ago