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3 years ago

8

A popular fast food restaurant sells, on average, 18 orders of fries every 3 minutes. Based on this information, how many orders

of fries does the restaurant sell in an hour?

1 answer:

Tatiana [17]3 years ago

7 0

360. Hope this helps.

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What is the solution set for the inequality 4 - 5g > 39?

katrin [286]

The solution set for the given inequality is $g > -7$

<u>Given the following inequality:</u>

$4 - 5g > 39$

<h3>What is an inequality?</h3>

An inequality can be defined as a mathematical relation that is typically used to compare two (2) integers or variables in an equation by illustrating any of the following:

Greater than (>).

Less than (<).

Greater than or equal to the other (≥).

Less than or equal to the other (≤).

Simplifying the inequality, we have:

$4 - 5g > 39\\\\5g > 4-39\\\\5g > -35\\\\g > -7$

Read more on inequality here: brainly.com/question/24372553

6 0

2 years ago

What is the answer?????

wolverine [178]

Answer:B

Step-by-step explanatioslope intercept is y=mx+b and choice B is NOT in that form so your answer would be B

8 0

3 years ago

WHATS THE PERIMITER PLS HELP ME

mihalych1998 [28]

I believe the answer is c

4 0

2 years ago

Twin brothers, Billy and Bobby, can mow their grandparent's lawn together in 97 minutes. Billy could mow the lawn by himself in

s2008m [1.1K]

Answer:

52 minutes i think im not sure i'm not in high school

Step-by-step explanation:

5 0

2 years ago

If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

5 0

3 years ago

Read 2 more answers