All categories

3 years ago

(5.2x + 36.4x + 52)/ (2.6x +13)

Mathematics

1 answer:

g100num [7]3 years ago

4 0

Combine like terms in the first set and get
41.6x +52/2.6x + 13

I got 16x + 4

You might be interested in

A van,a moving company charges 50.00 plus 5.50 by per mile. The table shows the total cost for the number of miles drivin

Anna71 [15]

y = 55/10x + 50 is the equation to represent this situation

8 0

2 years ago

184 is what percent more than 148

Alika [10]

It is 36 percent more

7 0

3 years ago

Find all values of k for which the equation 3x^2−4x+k=0 has no solutions.

dusya [7]

The given equation has no solution when K is any real number and k>12

We have given that

3x^2−4x+k=0

△=b^2−4ac=k^2−4(3)(12)=k^2−144.

<h3>What is the condition for a solution?</h3>

If Δ=0, it has 1 real solution,

Δ<0 it has no real solution,

Δ>0 it has 2 real solutions.

We get,

Δ=k^2−144 here Δ is not zero.

It is either >0 or <0

Δ<0 it has no real solution,

Therefore the given equation has no solution when K is any real number.

To learn more about the solution visit:

brainly.com/question/1397278

5 0

2 years ago

Read 2 more answers

Can someone solve this:

soldi70 [24.7K]

The answer is 3x-4y-6z

5 0

3 years ago

Larry has a gift card worth 400 for a local entertainment store Movies cost $20 each and newly released video games cost $50 eac

Vikki [24]

Answer:

All are correct.

Step-by-step explanation:

Let x be the number of movies and y be the number of newly released video games.

Larry has a gift card worth 400 for a local entertainment store Movies cost $20 each and newly released video games cost $50 each.

$20x+50y\leq 400$

Larry must purchase at least nine items.

$x+y\geq 9$

Check both inequalities of all given ordered pairs.

For (5,6),

$20(5)+50(6)\leq 400\Rightarrow 400\leq 400$

$5+6\geq 9\Rightarrow 16\geq 9$

Point (5,6) satisfy both inequalities.

For (10,4),

$20(10)+50(4)\leq 400\Rightarrow 400\leq 400$

$10+4\geq 9\Rightarrow 14\geq 9$

Point (10,4) satisfy both inequalities.

For (20,0),

$20(20)+50(0)\leq 400\Rightarrow 400\leq 400$

$20+0\geq 9\Rightarrow 20\geq 9$

Point (20,0) satisfy both inequalities.

For (15,2),

$20(15)+50(2)\leq 400\Rightarrow 400\leq 400$

$15+2\geq 9\Rightarrow 17\geq 9$

Point (15,2) satisfy both inequalities.

Therefore, all combination of movies and newly released video games Larry could purchase using his gift card.

4 0

3 years ago