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Snezhnost [94]
3 years ago
13

One edge of a cube measures 4.6 meters. What is the volume of the cube?

Mathematics
2 answers:
Serjik [45]3 years ago
6 0

A cube has all its 12 edges equal. Its volume is V=base\;area*height.

Base area of cube of side a is a^2.

The volume of a cube is V=a^3.

Here a=4.6\;m.

Now substitute the numerical value of a in the volume formula, then

V=4.6^3\\ V=97.336.

Thus the volume of the cube is 97.336\;m^3.


Oliga [24]3 years ago
3 0
97.336 is the answer i found it on a calculator, hope it helps :)
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Ronch [10]
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4 years ago
What is 10 to the negative 6th power?
Ivanshal [37]

Answer:

0.000001

Step-by-step explanation:

It is because 10 is represented as just like 10 and then in a certain place.  And then the negative means it is to the right of the decimal. 6th power means the 6th place. So, basically it means, 10 in the 6th to the right place which is 0.0000010. You do not need the last zero because there is no value after that, so 0.000001.

Sorry if I am wrong! Can I be brainlieest? TYSM

4 0
3 years ago
Provide a solution for the following equation: 3x + 2y=4
shtirl [24]

Answer:

One solution is to find x and y by doing the following:

Step-by-step explanation:

Let's solve for x.

3x+2y=4

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3x=−2y+4

Step 2: Divide both sides by 3.

x=-2/3y+4/3

Lets solve for y.

3x+2y=4

Step 1: Add -3x to both sides.

3x+2y+−3x=4+−3x

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Step 2: Divide both sides by 2.

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7 0
3 years ago
20r3 − 16r2 + 15r − 12
kati45 [8]

Answer:

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Step-by-step explanation:

Hope it helps

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If you are dealt 4 cards from a shuffled deck of 52 cards, find the probability of getting two queens and two kings.
Bingel [31]

<u>Given</u>:

If you are dealt 4 cards from a shuffled deck of 52 cards.

We need to determine the probability of getting two queens and two kings.

<u>Probability of getting two queens and two kings:</u>

The number of ways of getting two queens is 4C_2

The number of ways of getting two kings is 4C_2

Total number of cases is 52C_4

The probability of getting two queens and two kings is given by

\text {probability}=\frac{\text {No.of fanourable cases}}{\text {Total no.of cases}}

Substituting the values, we get;

probability=\frac{4C_2 \cdot 4C_2}{52C_4}

Simplifying, we get;

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Thus, the probability of getting two queens and two kings is 0.000133

7 0
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