take 16+5=21. 29-21=8 so answer is 8
First we need to determine the type of progression in the question.That's geometric progression. Because the pattern from one sequence to the others are about multiplying.
Second, determine the ratio of the progressionr = a₂/a₁
r = a₂ ÷ a₁
r = 1/2 ÷ 2
r = 1/2 × 1/2
r = 1/4
Third, determine the formula to know the recursive rulea₂ = a × 1/4
a₂ = 1/4 × a
Fourth, determine a₁. a₁ is the first term of the progressiona₁ = 2
Final answer:Recursive rule

a₁ = 2
Answer: 

Step-by-step explanation:
Let x represents the number of red roses and y represents the number of white roses.
Given : Javier is purchasing a bouquet of roses from a floral shop. He wants the bouquet to have at least 12 roses.
i.e. the required inequality for this statement will be :-
No. of red roses +No. of white roses ≥ 12
i.e. 
Also, Red roses cost $2.75 each and white roses cost $3.50 each and he wants to spend less than $35.
i.e. $2.75(No. of red roses)+$3.50(No. of white roses)≤ $35
i.e. 
Now, From (1) and (2) the system of inequalities represents the situation :


It has to be 3 boxes for all of them to fit
Answer:
<h2>
<em>X=</em><em>9</em></h2>
<em>Solution</em><em>,</em>
<em>
</em>
<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>