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Kipish [7]
3 years ago
15

Write an equation (-2, 10), (10, -14)

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
5 0

\bf (\stackrel{x_1}{-2}~,~\stackrel{y_1}{10})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{-14}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-14}-\stackrel{y1}{10}}}{\underset{run} {\underset{x_2}{10}-\underset{x_1}{(-2)}}}\implies \cfrac{-24}{10+2}\implies \cfrac{-24}{12}\implies -2

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{10}=\stackrel{m}{-2}[x-\stackrel{x_1}{(-2)}]\implies y-10=-2(x+2) \\\\\\ y-10=-2x-4\implies y=-2x+6

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First right answer gets brainliest
Finger [1]
Problem:
find line perpendicular to 4x+7y+3=0 passing through (-2,1).

Solution:
We will first find the general form of the perpendicular line.
The perpendicular line has the form
7x-4y+k=0 .........................(1)
by switching the coefficients of x and y, and switching the sign of one of the two coefficients.  This way, the slope of (1) multiplied by that of the original equation is -1, a condition that the two lines are perpendicular. The value of k is to be determined from the given point (-2,1).

To find k, we substitute x=-2, y=1 into equation (1) and solve for k.
7(-2)-4(1)+k=0
=>
k=14+4=18
Therefore the required line is
7x-4y+18=0

5 0
3 years ago
Read 2 more answers
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vova2212 [387]
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5 0
4 years ago
Please show work(15 points)
dexar [7]

Answer: 6 inches

Step-by-step explanation:

2 inches = 35 miles, so, 105 divided by 35 which is three, then 3 x 2  = 6

you're welcome

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3 years ago
What is the corollary to the polygon angle sum theorem?
Lina20 [59]
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3 years ago
Can someone please check my work for this one??
Anton [14]

Answer:

It is correct.  Believe me.  I am in <em>Honors</em> Math.

Step-by-step explanation:

4 0
3 years ago
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