Problem:
find line perpendicular to 4x+7y+3=0 passing through (-2,1).
Solution:
We will first find the general form of the perpendicular line.
The perpendicular line has the form
7x-4y+k=0 .........................(1)
by switching the coefficients of x and y, and switching the sign of one of the two coefficients. This way, the slope of (1) multiplied by that of the original equation is -1, a condition that the two lines are perpendicular. The value of k is to be determined from the given point (-2,1).
To find k, we substitute x=-2, y=1 into equation (1) and solve for k.
7(-2)-4(1)+k=0
=>
k=14+4=18
Therefore the required line is
7x-4y+18=0
Solve for w by simplifying both sides of the equation by isolating the variable then combining like terms w= -3
Answer: 6 inches
Step-by-step explanation:
2 inches = 35 miles, so, 105 divided by 35 which is three, then 3 x 2 = 6
you're welcome
Theorem<span> 6.2 </span>POLYGON<span> EXTERIOR </span>ANGLES THEOREM<span> - The </span>sum<span> of the measures of the exterior </span>angles<span>, one from each vertex, of a CONVEX </span>polygon<span> is 360 degrees. The </span>Corollary<span> to </span>Theorem<span> 6.2 - the measure of each exterior </span>angle<span> of a regular n-gon</span>
Answer:
It is correct. Believe me. I am in <em>Honors</em> Math.
Step-by-step explanation: