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3 years ago

Distribute the following :2/5(3x-8)

Mathematics

1 answer:

faltersainse [42]3 years ago

8 0

The answer would be 6x/5-16/5

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When simplifying 4x^3-10x^2+6x/2x^3+x^2-3x, what are the term(s) that can be cancelled

brilliants [131]

Answer:

x can be cancelled

Step-by-step explanation:

we are given

$\frac{4x^3-10x^2+6x}{2x^3+x^2-3x}$

Firstly, we will factor numerator and denominator

and then we can factor it

$4x^3-10x^2+6x=2x(2x^2-5x+3)$

$4x^3-10x^2+6x=2x(2x+1)(x-3)$

now, we can factor denominator

$2x^3+x^2-3x=x(2x^2+x-3)$

$2x^3+x^2-3x=x(x-1)(2x+3)$

now, we can replace it

$\frac{4x^3-10x^2+6x}{2x^3+x^2-3x}=\frac{2x(2x+1)(x-3)}{x(x-1)(2x+3)}$

we can see that

both terms are having x common

so, x can be cancelled

So,

x can be cancelled

3 0

3 years ago

Solve for x 5x+7=9x-25

Svetlanka [38]

Subtract 7 both sides
Subtract 9x both side
They cancel out
At the end you divide it
I don’t have access to paper right now sorry

6 0

3 years ago

Read 2 more answers

10 + 7m = 17

alisha [4.7K]

Subtract 10 and divide by 7

5 0

3 years ago

Read 2 more answers

Alexander is building a rectangular pen in his backyard for his dog. The pen will have a length of 13 feet and a width of 2x fee

Drupady [299]

4x+26

Step-by-step explanation:

to buy fencing, you need to find the perimeter of the pen. The perimeter is found by adding all sides together.

So, 13+13+2x+2x=4x+26

5 0

3 years ago

Please help me figure this out

Gnom [1K]

Answer:

True

(1) You can prove two triangles are similar using AA similarity.

(2)If side length of similar figure have ration $\frac{m}{n}$ then the ratio of surface areas will be: $\frac{m^2}{n^2}$

(3)If side length of similar figure have ratio of $\frac{2}{3}$ then perimeter will have ratio: $\frac{2}{3}$ .

False:

(1)If side length of similar figure have ration $\frac{m}{n}$ then the ratio of Volumes will be: $\frac{m^3}{n^3}$

(2)If side length of similar figure have ration $\frac{m}{n}$ then the ratio of surface area will be: $2\frac{m}{n}$

4 0

3 years ago