<C = 1/2(135 - 59)
<C = 1/2(76)
<C = 38
answer
A. 38°
Answer:
see explanation
Step-by-step explanation:
Using the trigonometric identity
sin²x + cos²x = 1
Consider the left side
2cos²A - 1 ← replace 1 by sin²A + cos²A
= 2cos²A - ( sin²A + cos²A)
= 2cos²A - sin²A - cos²A
= cos²A - sin²A = right side ⇒ verified
<h3>
Answer: 226 grams</h3>
==========================================
Explanation:
1/2 = 0.5
Every 60 days, the amount cuts in half.
We start with 904 grams and after 60 days, we have 904*0.5 = 452 grams left over.
After another 60 days, we have 452*0.5 = 226 grams left over.
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Alternative Method:
We can apply the half-life formula.
y = a*(0.5)^(x/H)
where,
- y = final amount after x days
- a = initial amount
- x = number of days that elapse
- H = number of days in a half-life
In this case,
- a = 904 is the starting amount
- H = 60 is the number of days until another half-life occurs
When x = 120 days go by, we have....
y = a*(0.5)^(x/H)
y = 904*(0.5)^(x/60)
y = 904*(0.5)^(120/60)
y = 904*(0.5)^(2)
y = 904*(0.25)
y = 226 grams of antimony left over.
This method is preferred over the first method if you have x be some non-multiple of 60, or if x is fairly large.
Answer:
x1=2 and x2 =-3/2
Step-by-step explanation:
2x^2-x-6=0 (quvadratic equation)
a=2, b=-1, c=-6
x1=(-b+sqrt(b^2-4ac))/2a
x1=(-(-1)+sqrt((-1)^2 - 4*2*(-6)))/2*2
x1 =(1+sqrt (1+48))/4
x1= (1+sqrt(49))/4
x1 =(1+7)/4
x1=8/4
x1=2
x2=(-b-sqrt(b^2-4ac))/2a
x2=(1-7)/4
x2=-6/4
x2=-3/2
Answer:
k = 10
Step-by-step explanation:
The external angle of a triangle is equal to the two opposite interior angles.
∠MYZ is an exterior angle of the triangle, thus
4k + 5 + 6k + 10 = 115, that is
10k + 15 = 115 ( subtract 15 from both sides )
10k = 100 ( divide both sides by 10 )
k = 10