Answer:10 presents fell off
Step-by-step explanation: to find 2/6 we can start with finding 1/6 because it’s easier. To do that we divide 30 by 6 which equals 5. because 5 is 1/6 5x2 is 2/6 so the answer is 10
since you have the 75, we know that a would equal 105 for line g , since a line = 180 degrees
so to make line f parallel with g it needs the same angles with line n as line g has
so if a = 105, then angle d would also need to be 105
The answer is D
Answer:
B
Step-by-step explanation:
There is a pattern. Subtract input from output and it is 11. So, if 11 is the pattern. subtract 51 from A,B,C, and D.Till one of them has the number 11 as answer. 51- 40=11. 40 = B
Answer:
I'll list the answers as coordinates (just input the second number in each coordinate)
(-2, 11)
(0, 1)
(2, -9)
(4, -19)
Step-by-step explanation:
So you see how the x column is filled out? You plug in the numbers in each area and solve for y.
So we start off with -2. You take the x out and place -2 instead. Your equation should look like this:
y = -5 (-2) + 1
Next you multiply -5 and -2, giving you 10. Your equation would look like this now:
y = 10 + 1
Next you add 10 and 1 together, and you have your answer. Keep doing the same thing, but instead of -2 for x, use 0, 2, and 4.
Hope I helped! Have a nice day or night! ^-^
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
