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3 years ago

8

How do you know if a coordinate on a graph is positive or negative?

2 answers:

andrey2020 [161]3 years ago

7 0

The positive is on the top right hand corner and the negative is the left lower corner.

Annette [7]3 years ago

5 0

Negative Slope<span>. </span>If<span> a line has a </span>positive slope<span> (i.e. m > 0 ), then y always increases when x increases and y always decreases when x decreases. Thus, the </span>graph<span> of the line starts at the bottom left and goes towards the top right. Thus, as x increases by 3 , y decreases by 4 , and as x decreases by 3 , y increases by 4 .

</span>

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What number am i thinking of?<br> a. 21<br> b. 9<br> c. 69<br> d. 7

icang [17]

Your thinking of the number 69

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2 years ago

Dvide. Give the quotient and the remainder.<br> 838/8

fiasKO [112]

Answer:

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2 years ago

If W(-10, 4), X(-3, -1), and Y(-5, 11) classify ΔWXY by its sides. Show all work to justify your answer.

solniwko [45]

Given:

The vertices of ΔWXY are W(-10, 4), X(-3, -1), and Y(-5, 11).

To find:

Which type of triangle is ΔWXY by its sides.

Solution:

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using distance formula, we get

$WX=\sqrt{(-3-(-10))^2+(-1-4)^2}$

$WX=\sqrt{(-3+10)^2+(-5)^2}$

$WX=\sqrt{(7)^2+(-5)^2}$

$WX=\sqrt49+25}$

$WX=\sqrt{74}$

Similarly,

$XY=\sqrt{\left(-5-\left(-3\right)\right)^2+\left(11-\left(-1\right)\right)^2}=2\sqrt{37}$

$WY=\sqrt{\left(-5-\left(-10\right)\right)^2+\left(11-4\right)^2}=\sqrt{74}$

Now,

$WX=WY$

So, triangle is an isosceles triangles.

and,

$WX^2+WY^2=(\sqrt{74})^2+(\sqrt{74})^2$

$WX^2+WY^2=74+74$

$WX^2+WY^2=148$

$WX^2+WY^2=(2\sqrt{37})^2$

$WX^2+WY^2=WY^2$

So, triangle is right angled triangle.

Therefore, the ΔWXY is an isosceles right angle triangle.

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galina1969 [7]

Answer:

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Step-by-step explanation:

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Nostrana [21]

|10| I think I learned this in sixth grade and pretty sure it's that

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