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pishuonlain [190]
3 years ago
7

In the diagram, line f is parallel to line , and line e intersects line and g.

Mathematics
1 answer:
Rama09 [41]3 years ago
5 0

Answer:

x=2°

Step-by-step explanation:

(5x+35)°=45° because they are alternative angle

5x+35°=45°

5x=45°-35°

5x=10°

x=10°/5

x=2°

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You roll a six-sided die twice. What is the probability of rolling a 3 and then a 5? A) 1 3 B) 1 6 C) 1 12 D) 1 36
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Answer:

D) 1/36

Step-by-step explanation:

You are trying to roll a 3 the first time, and then a 5 the second time. This means that order matters.

It is given to you, that you are rolling a standard die (6-sides). The dice is ordered in the following: 1, 2, 3, 4, 5, 6

The first time, you are rolling for a 3. Note that there is only one 3 in the sequence, so your chance of rolling a 3 is 1 out of 6: 1/6.

The second time, you are rolling for a 5. Note that there is only one 5 in the sequence, so your chance of rolling a 5 is 1 out of 6: 1/6.

Next, multiply the two fractions together to find the probability of rolling a 3 and then a 5:

1/6 x 1/6 = (1 x 1)/(6 x 6) = 1/36

D) 1/36 is your answer.

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4 0
3 years ago
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Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,
omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

<u>Pyramid A</u>

s = 4 -- base sides

V = 36 -- Volume

<u>Pyramid B</u>

s = 6 --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

V = \frac{1}{3} * B * h

Where B represents the area of the base equilateral triangle, and it is calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

B = \frac{1}{2} * s^2 * sin(60)

B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}

B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}

B = 4\sqrt 3

The height is calculated from:

V = \frac{1}{3} * B * h

This gives:

36 = \frac{1}{3} * 4\sqrt 3 * h

Make h the subject

h = \frac{3 * 36}{4\sqrt 3}

h = \frac{3 * 9}{\sqrt 3}

h = \frac{27}{\sqrt 3}

To calculate the volume of pyramid B, we make use of:

V = \frac{1}{3} * B * h

Since the heights of both pyramids are the same, we can make use of:

h = \frac{27}{\sqrt 3}

The base area B, is then calculated as:

B = \frac{1}{2} * s^2 * sin(60)

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B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}

B = 9\sqrt 3

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Where

B = 9\sqrt 3 and h = \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9 * 27

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➷ You have to collect like terms

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➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

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