Answer:
V = 282.10 cm³
Step-by-step explanation:
Use this equation to find the volume of the cone
Simplify the (3.5)²
V = 3.14(12.25)(22/3) Multiply
V = 282.10 cm³
If this answer is correct, please make me Brainliest!
They're all divisible by 9 and 3. They're all equal to each other.
Answer:
The second table
Step-by-step explanation:
To create table of points using the function,
, substitute the value of x in each case.
Thus,
For x = -1,
![f(-1) = 3(-1)^2 - 8(-1) + 2 = 3(1) + 8 + 2 = 3 + 8 + 2](https://tex.z-dn.net/?f=%20f%28-1%29%20%3D%203%28-1%29%5E2%20-%208%28-1%29%20%2B%202%20%3D%203%281%29%20%2B%208%20%2B%202%20%3D%203%20%2B%208%20%2B%202%20)
![f(-1) = 13](https://tex.z-dn.net/?f=%20f%28-1%29%20%3D%2013%20)
For x = 0
![f(0) = 3(0)^2 - 8(0) + 2 = 3(0) - 0 + 2 = 0 - 0 + 2](https://tex.z-dn.net/?f=%20f%280%29%20%3D%203%280%29%5E2%20-%208%280%29%20%2B%202%20%3D%203%280%29%20-%200%20%2B%202%20%3D%200%20-%200%20%2B%202%20)
![f(0) = 2](https://tex.z-dn.net/?f=%20f%280%29%20%3D%202%20)
For x = 1,
![f(1) = 3(1)^2 - 8(1) + 2 = 3(1) - 8 + 2 = 3 - 8 + 2](https://tex.z-dn.net/?f=%20f%281%29%20%3D%203%281%29%5E2%20-%208%281%29%20%2B%202%20%3D%203%281%29%20-%208%20%2B%202%20%3D%203%20-%208%20%2B%202%20)
![f(1) = -3](https://tex.z-dn.net/?f=%20f%281%29%20%3D%20-3%20)
For x = 2,
![f(2) = 3(2)^2 - 8(2) + 2 = 3(4) - 16 + 2 = 12 - 16 + 2](https://tex.z-dn.net/?f=%20f%282%29%20%3D%203%282%29%5E2%20-%208%282%29%20%2B%202%20%3D%203%284%29%20-%2016%20%2B%202%20%3D%2012%20-%2016%20%2B%202%20)
![f(2) = -2](https://tex.z-dn.net/?f=%20f%282%29%20%3D%20-2%20)
For x = 3,
![f(3) = 3(3)^2 - 8(3) + 2 = 3(9) - 24 + 2 = 27 - 24 + 2](https://tex.z-dn.net/?f=%20f%283%29%20%3D%203%283%29%5E2%20-%208%283%29%20%2B%202%20%3D%203%289%29%20-%2024%20%2B%202%20%3D%2027%20-%2024%20%2B%202%20)
![f(3) = 5](https://tex.z-dn.net/?f=%20f%283%29%20%3D%205%20)
The second table is the correct answer.
Answer: a) 9.23×10⁻⁶ and b) 0.00144
Step-by-step explanation:
Since we have given that
Number of cards = 52
a) Probability that we draw 3 aces and 2 kings.
As we know that
Number of aces = 4
Number of kings = 4
Number of cards drawn = 5
So, the probability becomes,
![\dfrac{^4C_3\times ^4C_2}{^{52}C_5}=\dfrac{24}{2598960}=9.23\times 10^{-6}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5E4C_3%5Ctimes%20%5E4C_2%7D%7B%5E%7B52%7DC_5%7D%3D%5Cdfrac%7B24%7D%7B2598960%7D%3D9.23%5Ctimes%2010%5E%7B-6%7D)
(b) a "full house" (3 cards of one kind, 2 cards of another kind)
Since there are 13 sets of each type and we have to select and 2 kinds of it, so, it becomes ![2\times ^{13}C_2](https://tex.z-dn.net/?f=2%5Ctimes%20%5E%7B13%7DC_2)
So, it becomes,
![\dfrac{2\times ^{13}C_2\times ^4C_3\times ^4C_2}{^{52}C_5}=\dfrac{24\times 156}{2598960}=\dfrac{3744}{2598960}=0.00144](https://tex.z-dn.net/?f=%5Cdfrac%7B2%5Ctimes%20%5E%7B13%7DC_2%5Ctimes%20%5E4C_3%5Ctimes%20%5E4C_2%7D%7B%5E%7B52%7DC_5%7D%3D%5Cdfrac%7B24%5Ctimes%20156%7D%7B2598960%7D%3D%5Cdfrac%7B3744%7D%7B2598960%7D%3D0.00144)
Hence, a) 9.23×10⁻⁶ and b) 0.00144