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3 years ago

14

write two different inequalities in which one of the solutions is the same as the solution to x - 23 = 192

1 answer:

Slav-nsk [51]3 years ago

3 0

Answer:

I don't no the answer sorry

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If each lap in a pool is 100 meters long, how many laps equal one mile? Round to the nearest tenth

andrew-mc [135]

Each lap in a pool = 100 meters long.
Find the total number of laps are there in one mile.
First, let’s identify the value of 1 mile in meters.
=> 1 mile = 1 609.34 meters
Now, let’s divide it by 100 to know how many laps are there:
=> 1 609.34 / 100
=> 16.0934
Round to the nearest tenths
=> 16.1
Thus, there are 16.1 laps in one mile in a pool. Every laps measures 100 meters long

8 0

4 years ago

Find the value of k given that both points lie on a line passing through the origin.

Bond [772]

Answer:

$k=-3$

Step-by-step explanation:

Since the line passes through the origin, it must be a proportional/direct variation equation.

Direct variation equations have the form:

$y=ax$

Where a is the constant of proportionality.

Let’s solve for a. We know that when x=5, y=40. So:

$40=5a$

Divide both sides by 5:

$a=8$

Therefore, our equation is:

$y=8x$

We want to find the value of k such that y=-24. So, subsitute -24 for y and k for x:

$-24=8k$

Divide both sides by 8:

$k=-3$

Hence, the value of k is -3.

6 0

3 years ago

2 3/5 x 3 1/3 answer

Semenov [28]

2×5+3 =13\5

3×3+1=13/3

13/5×

10/3

130÷15= 82/5

3 0

3 years ago

This is algebra 2. Would like an answer ASAP. Thanks! Between the two chunks of numbers, thats a division sign, not an addition

NeX [460]

Answer:

Simplified form of $\frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}$ is $\mathbf{\frac{1}{(x+3)(x+4)} }$

Option A is correct answer.

Step-by-step explanation:

We need to find simplified form of $\frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}$

Solving the given expression:

$\frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}$

First we find factors of $x^2+x-6$

$x^2+x-6 \\= x^2+3x-2x-6\\= x(x+3)-2(x+3)\\=(x-2)(x+3)$

So, factors of $x^2+x-6$ are $(x-2)(x+3)$

Now, fining the factors of $x^2+5x+4$

$x^2+5x+4\\=x^2+4x+x+4\\=x(x+4)+1(x+4)\\=(x+1)(x+4)$

So, factors of $x^2+5x+4$ are $(x+1)(x+4)\\$

Now the given expression will become:

$\frac{x+1}{(x-2)(x+3)}\div \frac{(x+1)(x+4)}{x-2}$

Now, converting division sign into multiplication sign:

$=\frac{x+1}{(x-2)(x+3)}\times \frac{x-2} {(x+1)(x+4)}\\Cancelling, \:common\:terms\\=\frac{1}{(x+3)(x+4)}$

So, simplified form of $\frac{x+1}{x^2+x-6}\div \frac{x^2+5x+4}{x-2}$ is $\mathbf{\frac{1}{(x+3)(x+4)} }$

Option A is correct answer.

4 0

3 years ago

John worked 40 hours and made $640. Tanya made $960 working for 60 hours. Who makes more per hour?

Levart [38]

Answer:

they make the same per hour

5 0

3 years ago