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Diano4ka-milaya [45]
4 years ago
5

Find the greatest common factor of 6a^2b^2c^2d and 2acd^2 A. acd B. 2acd C. 2acd^2 D. 2a^2b^2c^2d^2

Mathematics
2 answers:
babunello [35]4 years ago
8 0
The greatest common factor of 6a^2b^2c^2d and 2acd^2 is <span>2acd "B."</span>
STALIN [3.7K]4 years ago
5 0
Answer:

<span><span>2acd</span> </span>

Explanation:

Ironically it is the lowest index which is the Greatest common factor. (You cannot get more from a term than what is there.)

Make sure that a particular base is in both terms and use the lowest power for the GCF.

<span><span>2acd</span> </span>
There is no <span>b </span> factor in the second term, so it cannot be common.

The opposite happens when find the LOWEST common multiple . then it is the HIGHEST power which has to be used, because the LCM has to contain the whole of each term

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Answer:

7.81

Step-by-step explanation:

7 0
3 years ago
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Whats the awnser I need it asap
Dimas [21]
A is the right answer
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3 years ago
What is the product of the polynomial 2x^3 + 8x^2 + x + 3 times the<br> monomial x?
Elis [28]

Answer:

\huge\boxed{2x^4 + 8x^3 + x^2 + 3x}

Step-by-step explanation:

When we multiply a polynomial by a specific monomial, all terms in the polynomial get multiplied by the monomial.

So we can do this by term.

2x^3 \cdot x

Multiplying x by x to the something power will just increase the exponent on the x term by one (since powers are just x multiplied by itself). This means the exponent here will increase by 1, so this becomes 2x^4.

Same logic applies to the second term: 8x^2, raise the exponent by one, 8x^3.

For the third term, if there is no exponent on a term you can assume it's exponent is 1 (so x^1 in this case - as x^1=x). Again, using the same logic, this turns into x^2.

For the last term, when we multiply a constant by a variable, we get a term with a variable and a coefficient - the constant becomes the coefficient and the variable stays the variable. Therefore, 3 \cdot x = 3x.

Adding these terms all together gets us 2x^4 + 8x^3 + x^2 + 3x.

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8 0
4 years ago
Simplify<br><br>pls help me ASAP
Strike441 [17]

\dfrac{\left(\dfrac{4}{3}ab^3\right)\left(\dfrac{6}{2}a^4\right)}{a^5}=\dfrac{\left(\dfrac{\not4^2}{\not3_1}\cdot\dfrac{\not6^2}{\not2_1}\right)(aa^4)(b^3)}{a^5}=\dfrac{4a^5b^3}{a^5}=\boxed{4b^3}

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If 3/x = 5/y , what is the value of y/x?<br><br><br> (15 POINTS AND FREE BRAINIEST ANSWER!!)
Novay_Z [31]
3/x=5/y multiply both sides by y

3y/x=5  divide both sides by 3

y/x=5/3
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