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3 years ago

Find the value of x to the nearest tenth.

Mathematics

2 answers:

Scilla [17]3 years ago

5 0

Answer:

x = 8 .0 .

Step-by-step explanation:

Given : A right triangle with hypotenuse 10 units and angle 53 , 37 degree.

To find : Find the value of x to the nearest tenth.

Solution : We have given

Hypotenuse = 10 units.

Opposite side = x .

Adjacent side = y.

By the trigonometric ratio : sin(theta) = $\frac{opposite}{hypotenuse}$ .

sin(53) = $\frac{x}{10}$ .

0.798 = $\frac{x}{10}$ .

On multiplying 10 both sides.

0.798 * 10 = x

7.98 = x

Rounded to nearest tenth x = 8 .0

Therefore, x = 8 .0

BlackZzzverrR [31]3 years ago

4 0

Answer:

x = 8.0

Step-by-step explanation:

sin theta = opposite/ hypotenuse

sin 53 = x/10

Multiply by 10 on each side

10 sin 53= x

7.9863551 =x

Rounding to the nearest tenth

8.0 =x

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What is the length of segment AB? (4 points)

Sveta_85 [38]

Answer:

10 units

Step-by-step explanation:

$\sqrt{(0-6)^{2} +(10-2)^{2} }\\\\\sqrt{(-6)^{2}+(8)^{2} } \\\\\sqrt{36+64}\\\\\sqrt{100}\\\\10$

3 0

3 years ago

Find the gradient of the line segment between the points (-4,-5) and (2,-4).

dezoksy [38]

Answer:

1/6

Step-by-step explanation:

gradient= change in y/ change in x

-4--5/2--4= 1/6

1/6 is the gradient

8 0

3 years ago

Pyramid A is a square pyramid with a base side length of 12 inches and a height of 8 inches. Pyramid B is a square pyramid with

yan [13]

Answer:

The volume of pyramid B is 64 times the volume of pyramid A.

Step-by-step explanation:

Given:

Two square pyramids A and B.

Side Length of A, $s_A =$ 12 inches

Height of A, $h_A =$ 8 inches

Side Length of B, $s_B =$ 48 inches

Height of B, $h_B =$ 32 inches

To find:

How many times bigger is the volume of pyramid B than pyramid A?

$V_B$ is how many times bigger than $V_A$ ?

Solution:

First of all, let us have a look at the formula for volume of a pyramid:

$V=\dfrac{1}{3} \times \text{Area of Base} \times \text{Height}$

Here, base is square, so:

$V=\dfrac{1}{3} \times s^2 \times h$

Volume of pyramid A:

$V_A=\dfrac{1}{3} \times s_A^2 \times h_A$

$\Rightarrow V_A=\dfrac{1}{3} \times 12^2 \times 8 = 384\ inch^3$

Volume of pyramid B:

$V_B=\dfrac{1}{3} \times s_B^2 \times h_B$

$\Rightarrow V_B=\dfrac{1}{3} \times 48^2 \times 32 \\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 4^2 \times 4\\\Rightarrow V_B=\dfrac{1}{3} \times 12^2 \times 8 \times 64\\\Rightarrow V_B= 24576\ inch^3 = 384\times 64\ inch^3\\\Rightarrow V_B = V_A\times 64\ inch^3$

The volume of pyramid B is 64 times the volume of pyramid A.

3 0

3 years ago

Given ∆ABC≅∆PQR, mb=8v-9 , find m 31° b. 52° c. 49° d. 32°

Ipatiy [6.2K]

Here, 5v+6 = 8v-9
8v - 5v = 6 + 9
3v = 15
v = 15/3
v = 5

So, m<b = 5(5) + 6 = 25 + 6 = 31
As they are congruent, m<q would be same [ 31 degree ]

In short, Your Answer would be Option A

Hope this helps!

3 0

3 years ago

Which of the following are not congruence theorems for right triangles? Check all that apply.

Lera25 [3.4K]

Answer:

c) HH E)AA

Step-by-step explanation:

Two right angles can be proved congruent by LA,LL,HA,HL properties.

HH and AA are not congruence property.

Two triangles can be proved similar by AA property. All congruent triangles are similar but all similar triangles are not similar.Hence right triangles can not be proved congruent by AA property.

Among the options given Option C and E are not congruence property.

7 0

3 years ago

Read 2 more answers