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3 years ago

Three times a number, minus 5, is equal to two times the number, plus 9 find the number

Mathematics

2 answers:

STatiana [176]3 years ago

4 0

3x-5=2x+9 Solve for x

Mamont248 [21]3 years ago

4 0

14 is the answer.
3x-5=2x+9.

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a business shows a profit of $110 for selling 20 leather wallets how much profit would the business make if they sold 35 wallets

mafiozo [28]

Answer:

They would get 192.5

Step-by-step explanation:

First we need to find how much it cost per 1 so you will need to dovide 110 by 20 which equal 5.5

Then you will multiply 5.5*35 and get 192.5

8 0

3 years ago

marys age is 2 upon 3 that of peters age. two years ago marys age was 1 upon 2 of whats peters age will be in 5years time. how o

Nitella [24]

Answer:

the Peter age be 27

Step-by-step explanation:

Let assume peter be

And, then mary is 2p ÷ 3

The equation would be

2p ÷ 3 - 2 = 1 ÷ 2 (p + 5)

4p - 12 = 3p + 15

p = 27

So Peter age be 27

And, the mary age is

= 2 (27) ÷ 3

= 18

Hence, the Peter age be 27

4 0

3 years ago

If one ml. Equals one gram how much does a liter of water weigh

stich3 [128]

It will equal 1 Kg because 1ml = 1 gram

6 0

4 years ago

Read 2 more answers

Simlify: -5 1/4 (-7 1/2

myrzilka [38]

Answer: Hope This Helps!

Step-by-step explanation:

Exact Form:

315/8

Decimal Form:

39.375

Mixed Number Form:

39 3/8

7 0

3 years ago

Let P = 0.50.30.50.7 be the transition matrix for a Markov chain with two states. Let x0 = 0.50.5 be the initial state vector fo

pav-90 [236]

Answer:

Probability distribution vector = $\left(\begin{array}{c}0.375\\ 0.625 \end{array} \right)$

Step-By-Step Explanation

If $P=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right)$ is the transition matrix for a Markov chain with two states.

$x_{0}=\left(\begin{array}{c}0.5\\ 0.5 \end{array} \right)$ be the initial state vector for the population.

$X_{1}=P x_{0}=\left(\begin{array}{cc}0.5&0.3\\ 0.5&0.7 \end{array} \right) \left(\begin{array}{c}0.5\\ 0.5 \end{array} \right) =\left(\begin{array}{c}0.4\\ 0.6 \end{array} \right)$

$X_{2}=P^{2} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)$

$X_{3}=P^{3} x_{0}=\left(\begin{array}{c}0.38\\ 0.62 \end{array} \right)$

$X_{30}=P^{30} x_{0}=\left(\begin{array}{c}0.37499\\ 0.625 \end{array} \right)$

In the long run, the probability distribution vector Xm approaches the probability distribution vector $\left(\begin{array}{c}0.375\\ 0.625 \end{array} \right)$ .

This is called the steady-state (or limiting,) distribution vector.

4 0

3 years ago