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Lera25 [3.4K]
3 years ago
15

The final consumer of the product pays GST. Consider the following:

Mathematics
2 answers:
Marat540 [252]3 years ago
6 0

Answer:

????????????????????????????????????

Vlad [161]3 years ago
3 0

Answer:

pay the man g

Step-by-step explanation:

because i got bug brain

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The complement of an acute angle is an obtuse angle. <br><br> A.) True<br><br> B.) False
PilotLPTM [1.2K]
Your answer is False because obtuse angles are wide acute angles are right in the like this:^ but turn it to the west a right angle is like an L so your answer is False.

Your answer is False or B.
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3 years ago
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Which is true about the degree of the sum and difference of the polynomials 3x5y – 2x3y4 – 7xy3 and –8x5y + 2x3y4 + xy3?
Alekssandra [29.7K]
<span>First we have to find the sum and the difference of those polynomials- The sum is: ( 3 x^5y - 2 x^3y^4 - 7 xy^3 ) + ( - 8 x^5y + 2 x^3y^4 + xy^3 ) = 3 x^5 - 2 x^3y^4 - 7xy^3 - 8 x^5y + 2 x^3y^4 + xy^3 = - 5 x^5y - 6 xy^3. And the difference: ( 3 x^5y - 2 x^3y^4 - 7 xy^3 ) - ( - 8 x^5y + 2 x^3y^4 + xy^3 ) = 3 x^5y - 2 x^3y^4 - 7 xy^3 + 8 xy^5 - 2 x^3y^4 - xy^3 = 11 xy^5 - 4 x^3y^4 - 8xy^3. The highest exponent in both polynomials is 5. Answer: The degree of the polynomials is 5.</span>
7 0
3 years ago
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Mark set his watch 12.96 seconds behind, and it falls behind another 1.97 seconds every day. How many days has it been since Mar
iris [78.8K]

Answer:13 to 14

Step-by-step explanation:

5 0
3 years ago
What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove
wolverine [178]

Answer:

The solutions are:

b=0,\:b=4

Step-by-step explanation:

Considering the expression

  • \frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

Solving the expression

\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}

\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c

5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2

5b^3-10=6b^3-4b^2-10

\mathrm{Switch\:sides}

6b^3-4b^2-10=5b^3-10

6b^3-4b^2-10+10=5b^3-10+10

6b^3-4b^2=5b^3

\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}

6b^3-4b^2-5b^3=5b^3-5b^3

b^3-4b^2=0

Using\:the\:Zero\:Factor\:Principle: if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

So,

b=0,b-4=0

b=0,b=4

Therefore, the solutions are:

b=0,\:b=4

4 0
3 years ago
Read 2 more answers
Q: In an examination 14% of the students failed and 559 students passed. Find
topjm [15]
100% - 14% = 86%
86% of what gives you 559
559 * 100 = 55,900/86 = 650
650 students in total
650 - 559 = 91
Solution: 91 students failed
7 0
3 years ago
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