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Helen [10]
3 years ago
12

Help asap plz ill give a gold medal. the label on cars antifreeze claims to protect the car between -30celsius and 130celsius. t

o convert Celsius temperature Fahrenheit temperature, the formula is, c=5/9(F-32). Write an solve and inequality to determine the Fahrenheit temperature range at which antifreeze protects the car.
Mathematics
1 answer:
irga5000 [103]3 years ago
4 0
The inequality would start out looking like this:
-30\ \textless \  \frac{5}{9} (F-32)\ \textless \ 130
Now it's just a matter of solving the inequalities simultaneously. Get rid of the fraction by multiplying everything by 9:
-270\ \textless \ 5(F-32)\ \textless \ 1170
Then distribute the 5 into the parenthesis:
-270\ \textless \ 5F-160\ \textless \ 1170
Now add 160 everywhere:
-110\ \textless \ 5F\ \textless \ 1330
and finally divide everything by 5:
-22<F<266


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“the perimeter of the rectangle below is 90 units. find the length of side PS. write your answer without variables.”
Rzqust [24]

Answer:

19

Step-by-step explanation:

The opposite sides are equal, so:

PS = 3y+1

RS = 4y+2

QR = 3y+1

PQ = 4y+2

Therefore, we can set the perimeter 90 = PS+RS+QR+PQ

90 = (3y+1) + (4y+2) + (3y+1) + (4y+2), or,

90 = 2(3y+1) + 2(4y+2)

90 = 6y+2 + 8y+4

90 = 14y + 6

84 = 14y

y = 6

Then, we go back to the question. It's asking for the length of PS. PS = 3y+1, so we plug in 6 for y

3(6)+1

18 + 1 = <u>19</u>

5 0
3 years ago
I need help please help me
rusak2 [61]

Answer:

Ok,You need to put the value of x that appears in the table to give you the result of h (x)

1.h(x)=4x+5

h(-5)=4(-5)+5

h(-5)= -20+5

h(-5)= -15

2.h(-1)=4(-1)+5

  h(-1)= -4+5

  h(-1)= 1

3. h(1)=4(1)+5

   h(1)=4+5

   h(1)=9

4. h(3)=4(3)+5

   h(3)=12+5

   h(3)=17

5. h(4)=4(4)+5

    h(4)=16+5

    h(4)=21

Step-by-step explanation:

  x                  h(x)

-5                    -15

-1                       1

 1                       9

 3                      17

 4                      21

I hope this help.Please give me the brainliest

4 0
3 years ago
Leon usually does very well on tests, but he failed his most recent math exam. His teacher was very upset by Leon's performance
kondor19780726 [428]

Answer:

situational

Step-by-step explanation:

Based on the information provided within the question it seems that Leon's teacher made a situational attribution about his test performance. This term refers to when certain people believe that an individual's actions or behaviors are caused by a specific or various situational factors. Which is what his teacher is thinking by believing that his performance was affected by some problem or sickness (situational factors).

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

3 0
3 years ago
For the differential equations dydx=sqrt(y^2−36) does the existence/uniqueness theorem guarantee that there is a solution to thi
julsineya [31]

Answer:

1. (-4,6) there is no a solution to the equation through this point

2. (2,−6) there is no a solution to the equation through this point

3. (−5,39) there is a solution to the equation through this point

4. (−1,45)  there is a solution to the equation through this point

Step-by-step explanation:

Using the existence and uniqueness theorem:

Let:

F(x,y)=\sqrt{y^2-36} \\\\and\\\\\frac{\partial F}{\partial y} =\frac{y}{\sqrt{y^2-36} }

Now, let's find the domain of F(x,y), due to the square root:

y^2-36 \geq 0\\\\y^2\geq 36\\\\y \geq 6\hspace{12}or\hspace{12}y\leq-6

So the domain of the function is:

y \in R\hspace{12}y\geq6\hspace{12}or\hspace{12}y\leq-6

Now, due to the fraction \frac{\partial F}{\partial y} the denominator must be also different from 0, so:

y^2-36\neq0\\\\y \neq \pm6

So, the theorem  tells us that for each y_0\in R:\hspace{12}y_0>6\hspace{12}or\hspace{12}y_0 there exists a  unique solution defined in an open interval around x_0.

1. (-4,6)  there is no a solution to the equation through this point because y_0=6

2. (2,−6)  there is no a solution to the equation through this point because

y_0=-6

3. (−5,39) there is a solution to the equation through this point because

y_0>6

4. (−1,45)  there is a solution to the equation through this point because

y_0>6

6 0
3 years ago
What is the quotient
taurus [48]

The second one: 4 times 10 to the power of 12

5 0
3 years ago
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