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Gre4nikov [31]
3 years ago
13

How often does the water cycle occur on earth?

Chemistry
1 answer:
elena55 [62]3 years ago
7 0

Answer:

A

Explanation:

It doesnt depend on where you are in the world it will happen.

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Calculate the heat in joules "Q" needed to raise 27.0 g of water from 10.0 °C to 90.0 °C.​
Morgarella [4.7K]

Answer:

9028.8 J

Explanation:

The equation for working out the amount of thermal energy required is q = m c Δ T , where q is the amount of energy, m is the mass being heated up in grams, c is the specific heat capacity of what you're heating up in joules per gram per kelvin, and Δ T is the change in temperature in Kelvin.(Change in temperature will always give the same value,no matter Celsius or Kelvin)

mass = 27g, assuming specific heat capacity of water is 4.18 J/g*K, and the change in temperature is 90-10(=80)  , the energy needed to raise : 80 × 27 × 4.18 = 9028.8 J

5 0
3 years ago
Which non metal is a good conductor of heat and electricity ?​
torisob [31]

Answer:

Graphite

Graphite is a non-metal and it is the only non-metal that can conduct electricity. You can find non-metals on the right side of the periodic table and graphite is the only non-metal that is a good conductor of electricity.

4 0
3 years ago
Read 2 more answers
Which of the following would a chemist be most likely to study?
qaws [65]
B. because the other options are different sciences (biology and entomology)
5 0
3 years ago
At a certain temperature, 0.3411 0.3411 mol of N 2 N2 and 1.661 1.661 mol of H 2 H2 are placed in a 2.50 2.50 L container. N 2 (
Sveta_85 [38]

<u>Answer:</u> The equilibrium constant for the above reaction is 1.31

<u>Explanation:</u>

We are given:

Initial moles of nitrogen gas = 0.3411 moles

Initial moles of hydrogen gas = 1.661 moles

Equilibrium moles of nitrogen gas = 0.2001 moles

For the given chemical reaction:

                   N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

<u>Initial:</u>         0.3411      1.661

<u>At eqllm:</u>     0.3411-x  1.661-3x      2x

Evaluating for 'x', we get:

\Rightarrow (0.3411-x)=0.2001\\\\\Rightarrow x=0.3411-0.2001=0.141

Volume of the container = 2.50 L

The expression of K_c for the above equation follows:

K_c=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}

We are given:

[NH_3]=\frac{2\times 0.141}{2.50}=0.1128M

[N_2]=\frac{0.2001}{2.5}=0.08004M

[H_2]=\frac{1.661-(3\times 0.141)}{2.5}=0.4952M

Putting values in above expression, we get:

K_c=\frac{(0.1128)^2}{0.08004\times (0.4952)^3}\\\\K_c=1.31

Hence, the equilibrium constant for the above reaction is 1.31

5 0
3 years ago
Lead has a density of 11.3 g/cm3 . what is the volume of a 15.1 g block of lead?
natita [175]
Hey there:

density = 11.3 g/cm³

mass = 15,1 g

Therefore: 

D = m / V

11.3 = 15.1 / V

V = 15.1 / 11.3

V = 1.336 cm³
3 0
3 years ago
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