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Anna35 [415]
3 years ago
6

Solubility (polar vs. Nonpolar)

Chemistry
2 answers:
OverLord2011 [107]3 years ago
8 0
#.3 Ethanol as a Solvent. Ethanol is a very polar molecule due to its hydroxyl (OH) group, with the high electronegativity of oxygen allowing hydrogen bonding to take place with other molecules. The ethyl (C2H5<span>) group in ethanol is non-polar. Thus, ethanol can dissolve both polar and non-polar substances.
4.Benzene is non-polar </span><span>Electric charge in the molecules of non-polar solvents is evenly distributed, therefore the molecules have low </span>dielectric constant<span>. Non-polar solvents are hydrophobic (immiscible with water). Non-polar solvents are liphophilic as they dissolve non-polar substances such as </span>oils<span>, </span>fats<span>, </span>greases<span>.</span>
eduard3 years ago
4 0

<u>Explanation:</u>

It is given that polar solutes can be dissolved in polar solvents and non-polar solutes can be dissolved in non-polar solvent.

Alcohol being polar, does not dissolves ionic salt in it.

CCl_4 is a non-polar solvent.

From the given options:

1. NaCl: This is an ionic salt and hence, it will be soluble in water only.

2. I_2 : Iodine gas is a non-polar solute and hence, will be dissolved in non-polar solvent which is CCl_4

3. Ethanol: As, it is a polar molecule and is not an ionic salt, therefore it can be soluble in both water and alcohol.

4. Benzene: It is a non-polar molecule and hence, it will be dissolved in CCl_4

5. Br_2 : Bromine gas is a non-polar solute and hence, will be dissolved in CCl_4

6. KNO_3: This is an ionic salt and hence, it will be soluble in water only.

7. Toluene: This is a non-polar solute and hence, will be dissolved in CCl_4

8. Ca(OH)_2: This is an ionic salt and hence, it will be soluble in water only.

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In a 0.20 M solution, a weak acid is 3.0% dissociated.(a) Calculate the [H₃O⁺] , pH , [OH⁻], and pOH of the solution.
marin [14]

H₃O⁺ = 6.0×10^{-3}

OH = 1.7×10^{-12}

pH = 2.22

pOH = 11.78

<h3>What is pH?</h3>

The term pH, which originally stood for "potential of hydrogen" (or "power of hydrogen"), is used in chemistry to describe how acidic or basic an aqueous solution is. Lower pH values are summarized for acidic solutions (solutions with higher H+ ion concentrations) than for basic or alkaline solutions.

The pH scale is inversely indicates to the concentration of hydrogen ions in the solution and is logarithmic.

⇒pH = -log(a_{H+})

Acidic solutions are those with a pH below 7, and basic solutions are those with a pH above 7, at a temperature of 25 °C (77 °F). At this temperature, solutions with a pH of 7 are neutral (e.g. pure water). The pH neutrality relies on temperature, falling below 7 if the temperature rises above 25 °C.

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2 years ago
Which of the following is true about a system at equilibrium? a The concentration(s) of the reactant(s) is equal to the concentr
anyanavicka [17]

Answer:

c The concentration(s) of reactant(s) is constant over time.  

Step-by-step explanation:

When the reaction A ⇌ B reaches equilibrium, the concentrations of reactants and products are constant over time.

a is <em>wrong</em>, because the concentrations of reactants and products are usually quite different.

b is <em>wrong</em>, because both product and reactant molecules are being formed at equilibrium.

d is <em>wrong</em>. The rates of the forward and reverse reactions are equal, but they are not zero.

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How many molecules of NH3 are produced from 4.72x10 negative 4 power g of H2?
Delvig [45]
<span>9.40x10^19 molecules.
   The balanced equation for ammonia is:
 N2 + 3H2 ==> 2NH3
   So for every 3 moles of hydrogen gas, 2 moles of ammonia is produced. So let's calculate the molar mass of hydrogen and ammonia, starting with the respective atomic weights:
 Atomic weight nitrogen = 14.0067
  Atomic weight hydrogen = 1.00794

   Molar mass H2 = 2 * 1.00794 = 2.01588 g/mol
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   Moles H2 = 4.72 x 10^-4 g / 2.01588 g/mol = 2.34140921086573x10^-4 mol
   Moles NH3 = 2.34140921086573x10^-4 mol * (2/3) = 1.56094x10^-4 mol

Now to convert from moles to molecules, just multiply by Avogadro's number: 1.56094x10^-4 * 6.0221409x10^23 = 9.400197448261x10^19
   Rounding to 3 significant figures gives 9.40x10^19 molecules.</span>
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