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Sati [7]
3 years ago
15

Andrew wants to know how many 3/16 pound servings are in a bag containing 7/8 pound of granola.

Mathematics
2 answers:
PilotLPTM [1.2K]3 years ago
8 0
PART A:
x = how many 3/16 pound servings are in the bag.
3/16x = 7/8
PART B:
You need to turn these fractions into decimals:
3/16 = 0.1875
7/8 = 0.875
Rewrite the equation:
0.1875x = 0.875
Solve algebraically. Divide both sides by 0.1875.
0.875/0.1875 = 4.67
x = 4.67.
There are 4.67 3/16 pound servings in a bag containing 7/8 pounds of granola.
77julia77 [94]3 years ago
8 0

Answer :

PART A.

Let quantity of servings of granola in the bag = x pounds

\text{Part of the servings of granola in the bag = }\frac{3}{16}\\\\\text{Total quantity of servings of granola to be contained in the bag = }\frac{3}{16}\cdot x\\\\\text{Quantity of granola in the bag to be contained = }\frac{7}{8}

Now, Total quantity of servings of granola to be contained in the bag = Quantity of granola in the bag to be contained

\implies \frac{3}{16}\cdot x=\frac{7}{8}

PART B. Finding the value of the above expression :

\frac{3}{16}\cdot x=\frac{7}{8}\\\\\implies 3x\times 8=16\times 7\\\\\implies 3x=\frac{112}{8}\\\\\implies 3x=14\\\\\implies x=\frac{14}{3}

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Hope this helps! ☺

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Given one zero of the polynomial function, find the other zeros.
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Answer:

Step-by-step explanation:

You need to use synthetic division to do all of these.  The thing to remember with these is that when you start off with a certain degree polyomial, what you get on the bottom line after the division is called the depressed polynomial (NOT because it has to math all summer!) because it is a degree lesser than what you started.

a.  3I   1   3   -34   48

I'm going to do this one in its entirety so you get the idea of how to do it, then you'll be able to do it on your own.

First step is to bring down the first number after the bold line, 1.

3I   1    3    -34    48

   _____________

      1

then multiply it by the 3 and put it up under the 3.  Add those together:

3I    1    3    -34    48

           3

----------------------------

      1     6

Now I'm going to multiply the 6 by the 3 after the bold line and add:

3I    1     3     -34     48                                                                                                    

             3      18

_________________

      1      6     -16

Same process, I'm going to multiply the -16 by the 3 after the bold line and add:

3I      1      3      -34      48

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___________________

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That last zero tells me that x-3 is a factor of that polynomial, AND that the depressed polynomial is one degree lesser and those numbers there under that line represent the leading coefficients of the depressed polynomial:

x^2+6x-16=0

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Do the remaining problems like that one; all of them come out to a 0 as the last "number" under the line.

You got this!        

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