Answer:
<h2>
</h2>
Step-by-step explanation:
<h3>
</h3>
<u>First of all multiply through by 7</u>
We have
<h3>
</h3>
<u>Expand the terms in the bracket</u>
That's
<h3>
</h3>
<u>Add 16x to both sides</u>
That's
<h3>
</h3>
<u>Divide both sides by 30</u>
We have the final answer as
<h3>
</h3>
Hope this helps you
Answer:
The probability of 1 or less children from that group to learn how to swim before 6 years of age is 0.072
Step-by-step explanation:
In this case we need to compute the probability of none of these 12 children learns to swim before 6 years of age. This is given by:
p(0) = (1 - 0.312)^(12) = 0.688^(12) = 0.01124
We now need to calculate the probability that one child learns to swim before 6 years of age.
p(1) = 12*0.312*(1 - 0.312)^(11) = 3.744*(0.688)^(11)
p(1) = 3.744*0.01634
p(1) = 0.0612
The probability of 1 or less children from that group to learn how to swim before 6 years of age is:
p = p(0) + p(1) = 0.01124 + 0.0612 = 0.07244
Answer:
I think it could be 8+6+y
Step-by-step explanation: I dont really know but dont delete this. Can I be Brainlyest please?
U basically solve: (4sqrt8)*2 + (5 sqrt 12 + 6 sqrt 20)*2
