Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
Answer:32
Step-by-step explanation:32 because if you to b squared times 3 to the 4 power you will get 32
Answer:
-3.5
Step-by-step explanation:
Answer:
15.63 cm
literally all you need to do is substitute s for 2.5 which then is 2.5^3 which that simplified is 15.63 rounded to the nearest hundreth