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loris [4]
3 years ago
11

The formula for volume of a cube is V = s 3. What is the volume of a cube that has a side length of 2.5 centimeters?

Mathematics
1 answer:
MatroZZZ [7]3 years ago
5 0

Answer:

15.63 cm

literally all you need to do is substitute s for 2.5 which then is 2.5^3 which that simplified is 15.63 rounded to the nearest hundreth

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Figure AFigure B
Solnce55 [7]

Using the given information, the area of figure B is 315 ft²

<h3>Calculating Area </h3>

From the question, we are to calculate the area of figure B

In the given diagram, figure B is made up of a triangle and a square

∴ Area of figure B = Area of triangle + Area of square

Area of triangle = \frac{1}{2} bh

Where b is the base

and h is the height

Area of square = l^{2}

Where l is the length of a side

In the diagram,

l = b = 15 \ ft

h =12 \ ft

∴ Area of figure B = (\frac{1}{2}\times 15 \times 12) + 15^{2}

∴ Area of figure B = (15×6) + 225

∴ Area of figure B = 90 + 225

∴ Area of figure B = 315 ft²

Hence, the area of figure B is 315 ft²

Learn more on Calculating area here: brainly.com/question/23990217

#SPJ1

6 0
2 years ago
Area of a trapezium​
melamori03 [73]

Answer:

The area of a trapezium is computed with the following formula: Area = 1 2 × Sum of parallel sides × Distance between them.

Step-by-step explanation:

Hope it help! :)

7 0
3 years ago
Read 2 more answers
39-42 Differentiate <img src="https://tex.z-dn.net/?f=f" id="TexFormula1" title="f" alt="f" align="absmiddle" class="latex-formu
MAVERICK [17]

\text{Given that,}\\\\f(x) = \ln (x^2 - 2x)\\\\f'(x) = \dfrac  1{x^2 -2x} \cdot (2x - 2) = \dfrac{2(x-1)}{x(x-2)}\\\\\\\text{domain f(x): }   \{x| x < 0, x > 2 \}

4 0
2 years ago
English44 seconds ago
Stells [14]
Sorry if it’s wrong

3 0
3 years ago
A round trip from Montreal to LA is 2,688 miles and takes an airline 9 hours and 20 minutes. Given the outbound trip is the same
Ksju [112]

Answer:

4.074 hours

Step-by-step explanation:

r =

The formula for speed = Distance × Time

Hence,

Let the outbound speed = r

return trip speed = r + 25x/100 = 125r/100 = 1.25r

Note that: 9 hours and 20 minutes = 9.167

Let t1 and t2 be the time taken to travel on way and return journey.

t1 + t2 = 9 hr 10 min = 9.167 hrs

Hence:

2688/r + 2688/1.25r = 9.167

LCM(1.25r)

(2688 × 1.25) + 2688 /1.25r= 9.167

3360 + 2688 = 9.167 × 1.25r

6048 = 11.45875r

r = 6048/11.45875

Outbound trip rl = 527.8062615904876mph

Return trip speed = r + 25x/100 = 125r/100 = 1.25r

= 1.25 ×

659.75782699mph

Time for return trip = Distance/Speed

= 2,688 miles/659.75782699mph/

= 4.0742222222 hours

Approximately = 4.074 hours

8 0
3 years ago
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